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lesya [120]
3 years ago
7

Calculate AGrxn for this equation, rounding your

Chemistry
1 answer:
Agata [3.3K]3 years ago
4 0

Answer: \Delta G_{rxn}=130.19J

Explanation:

The balanced chemical reaction is,

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The expression for Gibbs free energy change is,

\Delta G_{rxn}=\sum [n\times \Delta G_(product)]-\sum [n\times \Delta G_(reactant)]

\Delta G_{rxn}=[(n_{CO_2}\times \Delta G_{CO_2})+(n_{CaO}\times \Delta G_{CaO})]-[(n_{CaCO_3}\times \Delta G_{CaCO_3})]

where,

n = number of moles

Now put all the given values in this expression, we get

\Delta G_{rxn}=[(1\times -394.4)+(1\times -604.17)]-[(1\times -1128.76)]

\Delta G_{rxn}=130.19J

Therefore, the gibbs free energy for this reaction is, +130.19 kJ

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Answer:

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Explanation:

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