Answer:
rate = [NO]²[O2]
Explanation:
The rate law for the reaction:
2 NO(g) + O2(g) → 2 NO2(g)
Is expressed in terms of reactants as follows:
rate = [NO]ⁿ[O2]ˣ
<em>Where n and x are the coefficients of the rate law.</em>
<em />
If [NO] is doubled, the rate increased 4 times. That is only possible if:
rate = [NO]²[O2]ˣ
Now, as [NO] is doubled and increased the rate 4 times, and [NO] + [O2] when doubled increased the rate 8 times, doubled [O2] implies increased the rate 2 times. That is only possible is:
<h3>rate = [NO]²[O2]</h3>
Answer:
Q = 3.59x10⁻⁸
Yes, precipitate is formed.
Explanation:
The reaction of Na₂S with Mn(CH₃COO)₂ is:
Na₂S(aq) + Mn(CH₃COO)₂(aq) ⇄ MnS(s) + 2 Na(CH₃COO)(aq).
The solubility product of the precipitate produced, MnS, is:
MnS(s) ⇄ Mn²⁺(aq) + S²⁻(aq)
And Ksp is:
Ksp = 1x10⁻¹¹= [Mn²⁺] [S²⁻]
Molar concentration of both ions is:
[Mn²⁺] = 0.015Lₓ (6.42x10⁻⁴mol / L) / (0.015 + 0.025)L = <em>2.41x10⁻⁴M</em>
[S²⁻] = 0.025Lₓ (2.39x10⁻⁴mol / L) / (0.015 + 0.025)L = <em>1.49</em>x10⁻⁴M
Reaction quotient under these concentrations is:
Q = [2.41x10⁻⁴M] [1.49x10⁻⁴M]
<em>Q = 3.59x10⁻⁸</em>
As Q > Ksp, <em>the equilibrium will shift to the left producing MnS(s) </em>the precipitate
Answer:
false
Explanation:
longer the wave length less frequency
Answer:
Assuming that the atmospheric pressure is standard, the temperature will rise steadily until it reaches 100°C
Answer:
https://www.chegg.com/homework-help/questions-and-answers/1-10-points-solution-15-percent-mass-kcl-benzene-new-boiling-point--901-c-b-921-c-c-821-c--q63751186
Explanation: Thats your answer