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pychu [463]
2 years ago
8

Calcium reacts with bromine to form calcium bromide. 2.1 Which atom will lose electrons? 2.2 How many electrons will it lose? 2.

3 Name the element that will gain electrons. 2.4 How many electrons does this atom gain? 2.5 Write down the symbol for each of the ions formed. 2.6 Write the chemical formula for calcium bromide.
Chemistry
1 answer:
Juli2301 [7.4K]2 years ago
8 0

<u>Answer:</u>

<u>For 2.1:</u> Calcium atom will loose electrons.

<u>For 2.2:</u> It will loose 2 electrons.

<u>For 2.3:</u> Bromine atom will gain electrons.

<u>For 2.4:</u> It will gain 1 electron.

<u>For 2.5:</u> The ions formed are Ca^{2+}\text{ and }Br^-

<u>For 2.6:</u> The chemical formula is CaBr_2

<u>Explanation:</u>

Calcium bromide is formed by the combination of calcium and bromine atoms. This compound is ionic compound because electrons get transferred from one atom to another atom.

Calcium is the 20th element of the periodic table. It is a metal and it looses its electrons. The electronic configuration for this element is 1s^22s^22p^63s^23p^64s^2

This element will loose 2 electrons and forms Ca^{2+} ion.

Bromine is the 35th element of the periodic table. It is a non-metal and it gains electrons. The electronic configuration for this element is [Ar]4s^23d^{10}4p^5

This element will gain 1 electron and forms Br^- ion.

The chemical formula for the given compound is CaBr_2

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A chemistry graduate student is given 125.mL of a 1.00M benzoic acid HC6H5CO2 solution. Benzoic acid is a weak acid with =Ka×6.3
lubasha [3.4K]

Answer:

53.9 g

Explanation:

When talking about buffers is very common the problem involves the use of the Henderson Hasselbach formula:

pH = pKa + log [A⁻]/[HA]

where  [A⁻] is the concentration of the conjugate base of the weak acid HA, and [HA] is the concentration of the weak acid.

We can calculate pKₐ from the given kₐ ( pKₐ = - log Kₐ ), and from there obtain the ratio  [A⁻]/HA].

Since we know the concentration of HC6H5CO2 and the volume of solution, the moles and mass of KC6H5CO2  can be determined.

So,

4.63 = - log ( 6.3 x 10⁻⁵ ) + log [A⁻]/[HA] = - (-4.20 ) + log [A⁻]/[HA]

⇒ log [A⁻]/[HA]  = 4.63 - 4.20 =  log [A⁻]/[HA]

0.43 = log [A⁻]/[HA]

taking antilogs to both sides of this equation:

10^0.43 =  [A⁻]/[HA] = 2.69

 [A⁻]/ 1.00 M = 2.69 ⇒ [A⁻] = 2.69 M

Molarity is moles per liter of solution, so we can calculate how many moles of  C6H5CO2⁻ the student needs to dissolve  in 125. mL ( 0.125 L ) of a 2.69 M solution:

( 2.69 mol C6H5CO2⁻ / 1L ) x 0.125 L  = 0.34 mol C6H5CO2⁻

The mass will be obtained by multiplying 0.34 mol times molecular weight for KC6H5CO2 ( 160.21 g/mol ):

0.34 mol x 160.21 g/mol = 53.9 g

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The estimated costs for remodelling the interior of an apartment are: three 1-gallon cans of paint at $15.44 each, two paint bru
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The total estimated cost with the appropriate significant figures is

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Any two non-zero digits that are separated by a zero are important. For instance, the number 108.0097 has seven significant digits. Every zero that is both to the right and left of a non-zero digit and the decimal point is never meaningful. For instance, the number 0.00798 had three significant digits.

Simply multiply the required number of goods by their individual costs, then add them all up to calculate this:

3*13,69= 41,07 2*9,53=19,06 \s1*135= 135

Total cost: $41,07 plus $19,06 plus 135 equals $55,13.

Thus, the overall price will be $195,13.

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suter [353]
The question in English is "<span>Determine the mass, in kg, of a material that is contained in a volume of 18L. It is known that the material density is 0.9 g/cm 3"

Answer: 
</span>
We can use a simple equation to solve this problem. <span>
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<span>Where </span>d <span>is the density, </span>m <span>is the mass and </span>v is the volume.

d = </span>0.9<span> g/cm³
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v = </span>18 L = 18 x 10³ cm³<span>

By applying the equation,
<span>    0.9 g/cm³ = m / </span></span>18 x 10³ cm³<span>
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Hence, the mass of 18 L of material is 16.2 kg.</span>
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