Answer:
9.60 ; - 60.96
Step-by-step explanation:
Given the function :
F(x)=6(x+1) /25, x=0, 1, 2, 3, 4.
x = 0
F(0)=6(0+1)/25 = 6/25 = 0.24
x = 1
F(1)=6(1+1)/25 = 12/25 = 0.48
x = 2
F(2)=6(2+1)/25 = 18/25 = 0.72
x = 3
F(2)=6(3+1)/25 = 24/25 = 0.96
x = 4
F(2)=6(4+1)/25 = 30/25 = 1.2
X ______0 _____ 1 ______ 2 ______ 3 ____ 4
P(x) ___ 0.24 __ 0.48 ___ 0.72 ____ 0.96 __ 1.2
Mean, μ = Σx*p(x) :
(0*0.24) + (1*0.48) + (2*0.72) + (3*0.96) + (4*1.2)
= 9.60
Variance : Σx²*p(x) - μ²
(0^2*0.24) + (1^2*0.48) + (2^2*0.72) + (3^2*0.96) + (4^2*1.2) - 9.6^2
= 31.2 - 92.16
= - 60.96
Hello from MrBillDoesMath!
Answer:
+\- 10i
Discussion:
Fortunately, I can do this one in my sleep...... );
+\- sqrt(-100) =
+\- 10 i where i = sqrt(-1)
Thank you,
MrB
Answer:
What is the probability both are math phobic? 0.49%
What is the probability at least one is math phobic? 9.31%
Step-by-step explanation:
In order to both be math phobic, both individuals has to be inside of the probability of 7%, that means 0.07*0.07 = 0.0049 = 0.49%
In order to at least one be math phobic there's some cases which satisfies the sentence:
Individual A is math phobic and B as well = 0.07*0.07 = 0.0049 = 0.49%
Individual A is math phobic, but B is not = 0.07*0.63 = 0.0441 = 4.41%
Individual A is not, but B is math phobic = 0.63*0.07 = 0.0441 = 4.41%
Suming the 3 possibles cases, the probability at least one is math phobic
= 9.31%
Answer:
776031942
Step-by-step explanation:
I'll answer your other questions if I know it
