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san4es73 [151]
2 years ago
13

I NEED THE WORK SHOW PLS HELP! FOR 30 POINTS!

Mathematics
2 answers:
snow_tiger [21]2 years ago
6 0
Triangle yes yes 36 sum but it should be fine like that islf y my usebf ur fbrain
Sladkaya [172]2 years ago
4 0

Answer:

Formula is: ( x - p )² + ( y - q )² = r², where p and q are coordinates of a center of a circle, and r is for radius.

Equation of a circle is:

B) (x-1)² + (y-1)² = 4

Step-by-step explanation:

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Is 16to 14 and 64to60 equivalent
stiks02 [169]
NO. They are not.

We can prove this by turning those numbers into fractions:

16 / 14 = 1.1428  ;  64 / 60 = 1.0667

Or simply:

64 / 16 = 4
60 / 14 = 4.29

To get the equivalent of 16 to 14; we must multiply both numbers by 4.

16 * 4 = 64
14 * 4 = 56

The equivalent of 16 to 14 is 64 to 56.

3 0
3 years ago
Factor the expression 2x^3-10x^2-5x+25. Show your work.
azamat

Step 1. Factor out common terms in the first two terms, then in the last two terms.

2x^2(x - 5) -5(x - 5)

Step 2. Factor out the common term x - 5

(x - 5)(2x^2 - 5)

4 0
3 years ago
What is the slope - intercept form of the equation if the line through the points (3,-1) and (-1,-5)
ikadub [295]

Answer:

Slope - intercept form:

B) y= x -4

Step-by-step explanation:

(3,-1) and (-1,-5)

Slope = (-5 + 1)/(-1 - 3)

Slope = -4 / -4

Slope = 1

Point slope form:

y + 1 = 1 (x - 3)

y +1 = x - 3

y = x - 4   <------------------slope - intercept form



7 0
3 years ago
Read 2 more answers
Identify the equation in slope-intercept form for the line containing the point (0,7) and perpendicular to y=−5/4x+11/4. HELP PL
777dan777 [17]

To write the equation of a line I need slope and y intercept (0,y)

I have y intercept (0,7)  of +7 as written in the equation

The equation y=-5/4x + 11/4 has a slope of -5/4

To get perpendicular slope is negated reciprocal

so take -5/4 and flip it -4/5 and change the sign (in this case negative to positive)  4/5

so the new equation is y=4/5x +7 (third one)

6 0
3 years ago
Read 2 more answers
What is the midpoints of a segment whose endpoints are (-3, 8) and (7, -2) ?
Sidana [21]
M = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})
M = (\frac{7 - (-3)}{2}, \frac{-2 + 8}{2})
M = (\frac{7 - 3}{2}, \frac{6}{2})
M = (\frac{4}{2}, 3)
M = (2, 3)
3 0
3 years ago
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