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kipiarov [429]
2 years ago
7

Balance the chemical equation by adding coefficients as needed. equation:

Chemistry
1 answer:
Rom4ik [11]2 years ago
7 0

Balance the chemical equation by adding coefficients as needed. equation:

4HCl + -1As2O3 + 4NaNo3 + -5H2O → 12No + -2H3AsO4 + 4NaCl      

Chemical Equation

A chemical equation is a symbolic representation of a chemical reaction in the form of symbols and formulae, where the reactant entities are given on the left and the product entities are given on the right, with a plus sign separating the entities in both the reactants and the products and an arrow pointing in the direction of the products to indicate the reaction's direction. The absolute values of the stoichiometric numbers are shown as coefficients next to the symbols and formulas of the entities. Jean Beguin drew the first chemical equation in 1615.

To learn more about the chemical equation refer here:

brainly.com/question/22817140

#SPJ4

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alculate the standard enthalpy of formation of ethanoic acid given that the standard enthalpy of combustion for carbon is –394 k
agasfer [191]

Answer:

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

Explanation:

C(g)+O_2(g)\rightarrow CO_2(g),\Delta H_{1, comb}=-394 kJ/mol...[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l),\Delta H_{2, comb}=-286 kJ/mol..[2]

CH_3COOH(l)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l),\Delta H_{3, comb}=-876 kJ/mol..[3]

The standard enthalpy of formation of ethanoic acid :

2C(g)+2H_2(g)+O_2(g)\rightarrow CH_3COOH, \Delta H_{4}=?..[4]

Using Hess's law to calculate :

2 × [1] + 2 × [2] - [3] = [4]

\Delta H_4=2\times (-394 kJ/mol)+2\times (-286 kJ/mol) - (-876 kJ/mol)

=\Delta H_4=-484 kJ/mol

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

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WHICH IS NOT A PROPERTY OF GOLD?
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Answer:

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=2&ved=2ahUKEwie2-mVj7vnAhVZCTQIHZu_C_oQFjABegQIBBAB&url=https%3A%2F%2Fbrainly.com%2Fquestion%2F10678573&usg=AOvVaw0r9hUMT8WrZ96qbkRaSJpX

Explanation:

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The correct answer would be false

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