Answer:
92gm
Explanation:
Atomic mass of Mg=24g=1 mole of Mg
∴ 24g =1 mole of Mg contain 6.022×10^23 atom
∴ 6gm contains 246.022×1023×6
=4×6.022×10^23 atoms
Now according to question, there are 6.022×1023 atoms of Na
23gm of Na contains 6.022×10^23 atoms
∴6.022×4×10^23 atoms of Na weighs 23×6.022×10^23×4/6.022×10^23⇒92gm
Answer:
It is liquid at most temperatures on Earth.
It is 12 to 1 or 12/1 miles of saline to L solution
As in relative abundance , one is take reference
So,
One is taken as 1:
Other is subtracted from it:
(1 - 0.6011)(atomic mass of Ga-71)
Equation can be written as:
<span>69.723 = (0.6011)(68.9256) + (1-0.6011)x </span>
<span>(1-0.6011) is the percentage abundance of Ga-71 expressed in percentage: </span>
<span>Solving for x </span>
<span>28.2918 = 0.3989 x </span>
<span>x= 70.9246.......</span>
Hey there!:
ΔTf = Kf * m
Molar mass glucose = 180 g/mol
number of moles glucose:
n = mass of solute / molar mass
n = 21.5 / 180
n = 0.119 moles glucose
Amount of solvent in kg = 255/1000 = 0.255 Kg
Molality = number of moles / solvent
m = 0.119 / 0.255
m = 0.466 moles/kg
Kf for water = - 1.86 ºC/*m
Therefore:
ΔTf = Kf * m
ΔTf = (-1,86) * 0.466
ΔTf = -0.86676 ºC
hope this helps!
