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Amiraneli [1.4K]
1 year ago
12

A study of college freshmen found that students who watched tv for more than one hour each night gained 15 pounds in the first s

emester, compared to those who watched less than one hour. they concluded that there is an association between watching tv and weight gain in college freshmen. which study design did they most likely use?
Mathematics
2 answers:
nasty-shy [4]1 year ago
4 0

Answer: C

For the people who want only one answer and not 2 for the question if you can only submit one answer :)

Artyom0805 [142]1 year ago
4 0

Answer:

C.  They most likely used an observational study asking students to keep track of their TV habits and weight.

A.  This is an experiment because a treatment was applied to a group.

Step-by-step explanation:

According to our question:

1. The study concluded that there is a relation between watching TV and the weight gain in college freshmen.

Now, this is possible when a group of college students were asked to participate to watch TV for more than 1 hour for a specific amount of time and have a record of their weights.

So, the study is an observational study where the habits and weights of college students were observed.

Hence, option C is correct.

2. The students were divided onto two groups where one group used the computer program and the other did not to check the improvement in the reading levels.

This means that the students were given a procedure to follow during the study in order to see the results..

So, the study is an experiment where a treatment is applied to the group of students.

Hence, option A is correct.

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3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

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# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

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∵ c² = a² + b²

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4 0
3 years ago
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Oof this is probably really simple to most of y'all but I'm out of it.
Lelechka [254]

Answers:

  • angle1 = 156 degrees
  • angle2 = 24 degrees

=======================================================

Explanation:

The two angles form a straight line, which is 180 degrees

Add up the angle expressions and set the sum equal to 180.

(angle1) + (angle2) = 180

(4x) + (x-15) = 180

(4x+x)-15 = 180

5x-15 = 180

5x = 180+15

5x = 195

x = 195/5

x = 39

We use that x value to find each missing angle

  • angle1 = 4x = 4*39 = 156 degrees
  • angle2 = x-15 = 39-15 = 24 degrees

Then notice how angle1+angle2 = 156+24 = 180 to verify the answer.

Side note: Angles that add to 180 are considered supplementary.

6 0
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