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nexus9112 [7]
2 years ago
13

Joy and Joey share a 18-ounce bucket of clay. By the end of the week, Joy has used

Mathematics
1 answer:
Ksivusya [100]2 years ago
8 0
3 ounces
explanation: 1/6 of 18 is 3 so 18-3= 15 and 2/3 of 18 is 12 so 15-12=3 ounces
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Triangle XYZ is reflected about the y-axis. What are the coordinates of X'?
ladessa [460]

Answer:

your answer has been attached

5 0
2 years ago
-6-t/4 =-1 Please solve for t<br> 10 points
USPshnik [31]

-6 - t/4 = -1

+6          +6

-----------------

-t/4    =   5

x -4          x -4

----------------

t   =  -20

Hope this helped! :D

5 0
2 years ago
Can someone help explain please
Vitek1552 [10]

Answer:

step by step^^ hope this helps

3 0
2 years ago
Jorden leaves home for school on his bike everyday at 6:00 AM, traveling at 32 km/h. one day he forgot his homework, which his m
densk [106]

Answer:

She caught up with Jordan at 6:39 AM

Step-by-step explanation:

We solve this question making linear functions for the distances that Jorden and his mom have driven, and then we equalize them to find the moment they caught up.

Jorden leaves home for school on his bike everyday at 6:00 AM, traveling at 32 km/h.

Her mom will have left 15 minutes after he left, when he will already have traveled \frac{15*32}{60} = \frac{32}{4} = 8\text{km}

So, his position after t minutes can be modeled by the following function:

J(t) = 8 + 32t

His mom

His mom goes after him starting from home, so the initial position is 0, with a velocity of 52 km/h. So her position can be modeled by the following function:

M(t) = 52t

At what time did she catch up with Jorden,

She catches up t minutes after 6:15 AM.

t is found when

M(t) = J(t)

So

8 + 32t = 52t

20t = 8

t = \frac{8}{20}

t = 0.4

0.4 of an hour is 0.4*60 = 24 minutes.

So she catched up with Jordan after 6:15 AM + 24 minutes = 6:39 AM

4 0
2 years ago
Cot y, if csc y =-10/3 and cos y&lt; 0
fredd [130]
\csc y=-\dfrac{10}3\implies\sin y=-\dfrac3{10}

\cos^2y=1-\sin^2y\implies \cos y=\pm\sqrt{1-\dfrac9{100}}=\pm\dfrac{\sqrt{91}}{10}

You're told that \cos y, so omit the positive root.

\cot y=\dfrac{\cos y}{\sin y}=\dfrac{-\frac{\sqrt{91}}{10}}{-\frac3{10}}=\dfrac{\sqrt{91}}3
7 0
3 years ago
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