The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.
<h3>What is speed?</h3>
Speed can be calculated as the ratio of distance traveled to the time taken.
The speed that a tsunami can travel is modeled by the equation
s = 356√d, where s is the speed in kilometers per hour and d is the average depth of the water in kilometers.
S = 356√d
200 = 356√d
√d = 200/356
= 0.5618
d = 0.5618^2
= 0.316 km
d = 0.32 km.
Thus, The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.
Learn more about speed;
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Answer:
(5, 9)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
x - 5y = -40
18x - 5y = 45
<u>Step 2: Rewrite Systems</u>
18x - 5y = 45
- Multiply both sides by -1: -18x + 5y = -45
<u>Step 3: Redefine Systems</u>
x - 5y = -40
-18x + 5y = -45
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Combine equations: -17x = -85
- Divide -17 on both sides: x = 5
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: x - 5y = -40
- Substitute in <em>x</em>: 5 - 5y = -40
- Isolate <em>y</em> term: -5y = -45
- Isolate <em>y</em>: y = 9
Find how much 3% of $5000 is. Then multiply the 3% by five and add it to 5000. I hope that didn’t sound confusing.
Answer:
3y^2 - (y + 2) (y - 2) = 0
<=> 3y^2 - (y^2 - 4) = 0
<=> 2y^2 + 4 =0
<=>y^2 + 2 = 0
=> Because y^2 is always equal or larger than 0, there is no real solution.
Hope this helps!
:)
Step-by-step explanation:
