Answer:
Yes we can conclude.
Step-by-step explanation:
The sampling distribution of
can be approximated as a Normal Distribution only if:
np and nq are both equal to or greater than 10. i.e.
Both of these conditions must be met in order to approximate the sampling distribution of
as Normal Distribution.
From the given data:
n = 50
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
np = 50(0.80) = 40
nq = 50(0.20) = 10
This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution
you would multiply speed by time
20 feet per second times 10 seconds = 200 feet total
It has 3 factors, 5 x and y
Answer:
you could do 4y times 2y which would be 80y plus 2y times 2y which would be 40y so then 40 y plus 80y equals 120y
Step-by-step explanation: