Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer:4
Step-by-step explanation:What +7=11 bause the () make a multiplication and 11x3=33
There are 2 parts to this question. 1. One would be to calculate the interest based on your balance and 2. then to add the late fee. Use the formula i = prt to calculate your simple interest. <em>i</em> represents the interest you will pay, <em>p</em> stands for the principal (balance on your credit card), and <em>t</em> stands for the period of time (related to a period of a year/annual percentage rate). The $1998 balance times 0.145 times 1/12 gives the interest amount of $24.14. So, $1998 + $24.14 + $37 = $2059.14 balance.
Answer:
490
Step-by-step explanation:
19.6
25
980
3920
4900
then add the decimal
490.0
Answer:
x = 80
Step-by-step explanation:
Because of the parallel lines and the transversal to the left,
x + 67 = 147
x = 80
