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barxatty [35]
1 year ago
5

Alicia runs a small business mowing yards in the summer. for every yard she mows, she earns $40. however, she spends part of thi

s money on gasoline for her lawnmower. each gallon of gasoline costs $3. write an expression for the amount of money that alicia earns in a day, where y is the number of yards she mows and g is the number of gallons of gasoline she buys.
Mathematics
2 answers:
goldfiish [28.3K]1 year ago
8 0

Answer: $40y − $3g

Step-by-step explanation:

kipiarov [429]1 year ago
6 0

An expression for the amount of money that Alicia earns in a day is 40y-3g.

Given that, Alicia runs a small business mowing yards in the summer. For every yard she mows, she earns $40. However, she spends part of this money on gasoline for her lawnmower. Each gallon of gasoline costs $3.

We need to find an expression for the given situation.

<h3>What is an expression?</h3>

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Now, expression =40y-3g

Therefore, an expression for the amount of money that Alicia earns in a day is 40y-3g.

To learn more about an expression visit:

brainly.com/question/21751419.

#SPJ1

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egoroff_w [7]

Answer:

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6 0
3 years ago
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Sam invests $6000 in two different accounts. The first account paid 12 %, the second account paid 7 % in interest. At the end of
Lunna [17]

Answer:

The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

Let x be the amount in the account at 12% interest

So, 6000-x is the amount in the second account at 7% interest

SI = \frac{P \times T \times R}{100}

First account:SI=\frac{x \times 1 \times 12}{100}

Second account : SI =\frac{(6000-x) \times 1 \times 7}{100}

We are given that At the end of the first year he had earned $590 in interest.

So, \frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400

So,the amount in the account at 12% interest is $3400

The amount in the second account at 7% interest =6000-x=6000-3400=2600

Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

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