Question

A 60-m long wire is coiled so that it makes a coil containing 140 square loops, one on top of each other. if the wire carries a current of 21 a, what is the magnetic dipole moment of the coil?

Answer 1

A 60-m long wire is coiled so that it makes a coil containing 140 square loops, one on top of each other. if the wire carries a current of 21 a, the magnetic dipole moment of the coil will be 0.24 Am2

Dipole moment = i * A

Area = ?

given total length of the wire = 60 m number of square loops = 140total length of the wire  =  n * ( circumference of one loop) circumference of one loop = total length of the wire   / n  = 60 / 140 = 0.429 m circumference of one loop  = 4 * (side of the square )                                  0.429 = 4 * a a = $0.107 m$

Area of  loop = $a^{2}$=  $(0.107)^{2}$  = $0.01145 m^{2}$

Dipole moment = i * A  = 21 * 0.01145 = 0.24 A  $m^{2}$

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