Answer:
It helps you see the visual move of what you were doing. If you weren't moving anything it would help you see if it is true or false. Say you put a dot on the origin (0,0), then you have to go (x+7,y+3) then moving it on a graph would help show you. So overall it's a visual help to people.
g(θ) = 20θ − 5 tan θ
To find out critical points we take first derivative and set it =0
g(θ) = 20θ − 5 tan θ
g'(θ) = 20 − 5 sec^2(θ)
Now we set derivative =0
20 − 5 sec^2(θ)=0
Subtract 20 from both sides
− 5 sec^2(θ)=0 -20
Divide both sides by 5
sec^2(θ)= 4
Take square root on both sides
sec(θ)= -2 and sec(θ)= +2
sec can be written as 1/cos
so sec(θ)= -2 can be written as cos(θ)= -1/2
Using unit circle the value of θ is 
sec(θ)= 2 can be written as cos(θ)=1/2
Using unit circle the value of θ is 
For general solution we add 2npi
So critical points are

Answer:
only 20 students would
Step-by-step explanation:
the probability would be very since it is 20 out of 115. i hope this helped
Answer:
25 so C
Step-by-step explanation:
The width of his office on the floor plan is 2.5 in.