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dolphi86 [110]
3 years ago
5

What is the mode of the following numbers? 2, 5, 11, 7, 5

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
5 0
5 is the mode because wit occurred the most often
WINSTONCH [101]3 years ago
5 0

The mode of this set of numbers is 5.

The mode of a set of numbers, is the most common/frequent number within the set. Since there are two 5's but only one of each other number. Thus making 5 the mode.

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(2h3 + 6h) + (3h3 - 7h - 3) standard form sum or difference.​
worty [1.4K]

Answer:

5h^3- h - 3

Step-by-step explanation:

Given

(2h^3 + 6h) + (3h^3 - 7h - 3)

Required

Standard form

We have:

(2h^3 + 6h) + (3h^3 - 7h - 3)

Remove bracket

(2h^3 + 6h) + (3h^3 - 7h - 3) =2h^3 + 6h + 3h^3 - 7h - 3

Collect like terms

(2h^3 + 6h) + (3h^3 - 7h - 3) =2h^3 + 3h^3+ 6h  - 7h - 3

(2h^3 + 6h) + (3h^3 - 7h - 3) = 5h^3- h - 3

Hence, the standard form is:

5h^3- h - 3

3 0
2 years ago
Please help!!!!!!!!!
Xelga [282]

Answer:

uhm wrong guestion

Step-by-step explanation :

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7 0
3 years ago
A Rectangular has area 12a^2 and perimeter 14a what are the dimensions of this Rectangular?​
Nataliya [291]

9514 1404 393

Answer:

  3a by 4a

Step-by-step explanation:

For dimensions L and W, the area and perimeter are ...

  A = LW = 12a^2

  P = 2(L+W) = 14a

Using the second equation, we can find L:

  L +W = 7a . . . . . divide by 2

  L = 7a -W

Substituting into the area formula gives the quadratic ...

  (7a -W)(W) = 12a^2

  W^2 -7aW +12a^2 = 0 . . . . arrange in standard form

  (W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)

Then we have the two solutions ...

  W = 3a, L = 4a

  W = 4a, L = 3a

The rectangle dimensions are 3a by 4a.

5 0
3 years ago
John has 2456 pennies in his coin collection he has the same number of pennies in each of the three boxes estimate to the neares
Keith_Richards [23]
If I read correctly, 2456 pennies needs to be divided simply by 3 then rounded to the nearest hundredth. So you would do 2456/3 3 goes into 24 how many times? Then 3 goes into 5 how many times, then continue the pattern. Once you've gotten a decimal to the thousandth, round the number to the hundredth and there you go
5 0
3 years ago
Solve the problem by multiplying first. A clothing store is having a sale on shirts and jeans. Four shirts and two pairs of jean
ella [17]

We will solve this by suing simultaneous equations,

⇒ 5s + 3j = 87

    4s + 2j = 64

Multiply the first equation with 4 and the second one with 5, this is to get one of the values equal so that we can cancel them out,

⇒ (5s + 3j = 87) × 4

    (4s + 2j = 64) × 5

∴ ⇒ 20s + 12j = 348

       20s + 10j = 320

Subtract both the equations. This is how your result (after subtraction) should look like,

  ⇒ 2j = 28

∴ ⇒ j = $14

Now replace the value of 'j' in one of the original equations,

⇒ 4s + 2(14) = 64

⇒ 4s + 28 = 64

⇒ 4s = 64 - 28

⇒ 4s = 36

∴ ⇒ s = $9

Therefore, one pair of jeans cost $14 and a shirt costs $9

Hope you understood! Feel free to ask me if you didn't understand a step.

5 0
2 years ago
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