I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,
So,
So,
Hope this helps you!
1. 3x³-2x²+1x
2. 6y⁴+2y³-8y
3.-3m³-12m²+3m
4. 4d⁴-3d³+d²
5. -w⁵-3w³
6. -a⁴-3a³
Answer:
D.
Step-by-step explanation:
Translates horizontally 3.5 units right.
Y=3x+19
You add 3x to each side. Because your trying to get y by its self like y=mx+b.
Step-by-step explanation:
For no 1...
The range is [ -9, -7, 1]
For no 2....
The range is [-12, -10, -2]
For no 3.....
The range is [-11, -8, 4]