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Leto [7]
3 years ago
9

Seventy five thousandths to .75

Mathematics
1 answer:
fomenos3 years ago
6 0
Its equal because thousandths comes after the .
Hope this helps! :)
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The initial cost to drill a well is $210000. the daily rate to operate the well is $500. The current selling price is $65 per ba
SVETLANKA909090 [29]

Hi there!

There is an initial cost of $210,000 (which you're just going to pay once)

Then it costs $500 per day to operate.

The number of days is represented by "x".


Your equation in function notation should look like this :

f(x) = 500x + 210,000


There you go! I really hope this helped, if there's anything just let me know! :)

8 0
3 years ago
I will give brainliest if you answer this question !!!
yanalaym [24]

Answer:

A) 2

Step-by-step explanation:

Start off with the given information. The question states that the x-int. is 4, so you should recognize that there is a point at (4,0). Plug the point into the equation.

k(4) + 2(0) + 8 = 0

Now simplify the equation.

4k + 0 + 8 = 0

Isolate the variable, make sure it's on its own side.

4k = 8

Now get the k by itself to solve the equation. Divide both sides by 4.

k = 2

7 0
3 years ago
Please help, I’ll mark as brainliest!! The picture is above :)
Ray Of Light [21]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable

Exact Form:

x = - 25/8 \frac{x}{y}

Decimal Form:

x = -3.125

Mixed Number Form:

x = - 3/1/8 \frac{x}{y}

Step-by-step explanation:

5 0
2 years ago
I need help really bad
sdas [7]

Answer:

the x intercept=(-6,0) and y intercept=(0,14)

Step-by-step explanation:

i used math may but put the m as w, it works

5 0
2 years ago
A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?
AlekseyPX

Answer:

The width of the sandbox is 42\frac{2}{3} \ ft.

Step-by-step explanation:

Given,

Area of the sandbox = 10\frac{2}{3}=\frac{32}{3}\ ft^2

Length = \frac{1}{4}\ ft

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

Area = Length\times Width

On substituting the given values, we get;

\frac{1}{4}\times w=\frac{32}{3}\\

By cross multiplication method, we get;

w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft

Hence The width of the sandbox is 42\frac{2}{3} \ ft.

5 0
3 years ago
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