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3 years ago

What is the sum of all the integers between the square root of 10 and the square root of 47

2 answers:

8 0

What's the square root of 10 ?
   3²=9 and 4²=16
   So √10 is somewhere between 3 and 4 .

What's the square root of 47 ?
   6²=36 and 7²=49
   So √47 is somewhere between 6 and 7 .

The integers between √10 and √47 are 4, 5, and 6 .

Their sum is (4 + 5 + 6) = 15 .

insens350 [35]3 years ago

5 0

First estimate the square root of 10, about 3.16
and then the square root of 47, about 6.85
now what are the integers in between 3.16 and 6.85:
4,5,6
now add them all
4+5+6
=15
Hope this helps.

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Range: (844.9,1333.7)

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Step-by-step explanation:

We are given the following information in the question:

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Range rule thumb:

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Answer is given below

Step-by-step explanation:

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3 years ago

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