What is the sum of all the integers between the square root of 10 and the square root of 47
2 answers:
What's the square root of 10 ? 3²=9 and 4²=16 So √10 is somewhere between 3 and 4 . What's the square root of 47 ? 6²=36 and 7²=49 So √47 is somewhere between 6 and 7 . The integers between √10 and √47 are 4, 5, and 6 . Their sum is (4 + 5 + 6) = 15 .
First estimate the square root of 10, about 3.16 and then the square root of 47, about 6.85 now what are the integers in between 3.16 and 6.85: 4,5,6 now add them all 4+5+6 =15 Hope this helps.
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