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kati45 [8]
3 years ago
12

How much money should be deposited today in an account that earns 3 % compounded semiannually so that it will accumulate to $ 80

00 in three​ years?
Mathematics
1 answer:
Kipish [7]3 years ago
8 0

Answer:

The amount of money which should be deposited is $ 7316.627

Step-by-step explanation:

Given as :

Let the principal  = p

The interest rate compounded semiannually = 3 %

Time period = 3 years

The amount after three years = A = $ 8000

Now, Amount = Principal × (1 +\frac{Rate}{2\times 100})^{2\times Time}

Or,      $ 8000 = Principal × (1 +\frac{3}{2\times 100})^{2\times 3}

Or,      $ 8000 = p × (\frac{203}{200})^{6}

Or,      p = \frac{8000}{1.0934}

∴         p = $ 7316.627  

Hence The amount of money which should be deposited is $ 7316.627 Answer

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Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan
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(a) Null Hypothesis, H_0 : \mu \leq 41  

    Alternate Hypothesis, H_A : \mu > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let \mu = <u><em>mean sunspot activity during the Spanish colonial period.</em></u>

(a) Null Hypothesis, H_0 : \mu \leq 41     {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, H_A : \mu > 41     {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean = 47

            σ = population standard deviation = 35

            n = sample of periods from Spanish colonial times = 40

So, <em><u>the test statistics</u></em>  =  \frac{47-41}{\frac{35}{\sqrt{40} } }

                                      =  1.08

(b) The value of z test statistics is 1.08.

(c) <u>Now, the P-value of the test statistics is given by;</u>

                P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

                              = 1 - 0.8599 = <u>0.1401</u>

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

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Quadrilateral DEFG has vertices D(−2,4) , E(4,7) , F(10,3) , and G(8,0) .
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A rotation 270° counterclockwise about the origin is the same as rotation 90° clockwise about the origin and has a rule:

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