Question

Which expressions are equivalent to − 56 z + 28 −56z+28minus, 56, z, plus, 28? Choose 2 answers: Choose 2 answers: (Choice A) A 1 2 ⋅ ( − 28 z + 14 ) 2 1 ​ ⋅(−28z+14)start fraction, 1, divided by, 2, end fraction, dot, left parenthesis, minus, 28, z, plus, 14, right parenthesis (Choice B) B ( − 1.4 z + 0.7 ) × 40 (−1.4z+0.7)×40left parenthesis, minus, 1, point, 4, z, plus, 0, point, 7, right parenthesis, times, 40 (Choice C) C ( 14 − 7 z ) ⋅ ( − 4 ) (14−7z)⋅(−4)left parenthesis, 14, minus, 7, z, right parenthesis, dot, left parenthesis, minus, 4, right parenthesis (Choice D) D ( 8 z − 4 ) ( − 7 ) (8z−4)(−7)left parenthesis, 8, z, minus, 4, right parenthesis, left parenthesis, minus, 7, right parenthesis (Choice E) E − 2 ( − 28 z − 14 ) −2(−28z−14)minus, 2, left parenthesis, minus, 28, z, minus, 14, right parenthesis

Answer 1

Answer:

$(D)-2(28z-14) \: and\:\\(E) -7(8z-4)$

Step-by-step explanation:

We are to determine which of these expressions are equivalent to: $-56 z + 28$

$(A)\frac{1}{2}\cdot(-28z+14) \\(B)(-1.4z+0.7)40\\(C)(14-7z)\cdot(-4)\\(D)(8z-4)(-7)\\(E)-2(-28z-14)$

$-56 z + 28$

• If we factor out -2

$-56 z + 28=-2(\frac{ -56 z}{-2} + \frac{28}{-2})=-2(28z-14)$

• If we factor out -7

$-56 z + 28=-7(\frac{ -56 z}{-7} + \frac{28}{-7})=-7(8z-4)$

Therefore, the two equivalent expressions are:

$-2(28z-14) \: and\: -7(8z-4)$