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N76 [4]
4 years ago
8

Estimate the product by rounding In 2 times 6.254

Mathematics
1 answer:
Nadusha1986 [10]4 years ago
8 0
Well it would equal 12.508 so, 13 I guess.
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About 36,100,000 households in the U.S. have cats and about 43,300,000 households have dogs. About how may more households dogs
Svetllana [295]
Theres about a 7,200,000 difference between household dogs vs household cats 
5 0
3 years ago
Points m is the midpoint of FG. Can you determine the value of a?
GenaCL600 [577]

Using the midpoint concept, it is found that the value of a is of a = 2.

<h3>What are the coordinates of the points?</h3>

Researching this problem on a search engine, the coordinates are given as follows:

  • F(b + 1, a + 2).
  • M(3,5).
  • (2a, 3b+3).

<h3>What is the midpoint concept?</h3>

The midpoint between two points is the halfway point between them, and is found using the mean of the coordinates.

Hence the following system of equations can be built:

(b + 1 + 2a)/2 = 3.

b + 1 + 2a = 6.

b = 5 - 2a.

(a + 2 + 3b + 3)/2 = 5

a + 3b + 5 = 10

a + 3b = 5.

Since b = 5 - 2a, we have that:

a + 15 - 6a = 5.

5a = 10

a = 10/5

a = 2.

The value of a is of a = 2.

More can be learned about the mid-point concept at brainly.com/question/10956693

#SPJ1

6 0
2 years ago
Tori rolls three numbered 1 though 6. She records it weather each cube lands on an even or odd number
SVEN [57.7K]

Answer:

480 times

Step-by-step explanation:

Given

n = 50 ---- total number of rolls

See attachment for complete question

Required

Times OO will appear in a roll of 2000 times

From the attached bar graph,

n(OO) = 12

So, the occurrence of OO in 2000 rolls is:

OO = \frac{n(OO)}{n} * 2000

OO = \frac{12}{50} * 2000

OO = 0.24 * 2000

OO = 480

3 0
3 years ago
Fill in the blanks with the correct missing term of each given sequence<br>8,11,_,17,20​
lutik1710 [3]

Answer:

14 i think

Step-by-step explanation:

im not that sure but yeah

8 0
3 years ago
Read 2 more answers
You roll two dice. What is the probability that the sum of the dice is greater than 7 and one dice shows a 2? A 6x6 table of dic
vesna_86 [32]
In this question, the condition asked is two which was
1. The dice sum >7 (notice that >7 mean at least 8)
2. One of the two dice show a 2

It will be easier to fulfill the No.2 condition first so you can divide the probability into two,
Case 1: 1st dice show 2: then the second dice need to be 6 to made it sum>7
Case 2:2nd dice show 2: then the second dice need to be 6 to made it sum>7

The probability for a dice showing 2 is 1/6. The probability for a dice showing 6 is 1/6. Then the probability is 1/6 * 1/6= 1/36 for each case
Since case 1 and case 2 has same probability, then you just need to multiply 1/36 *2 = 1/18
5 0
4 years ago
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