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2 years ago

Circle the division problem that does not belong with the other three. Explain 621/6 384/3 719/7 514/5

Mathematics

1 answer:

dsp732 years ago

8 0

384/3. because it comes out even..128..the rest won't

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write a linear equation in slope-intercept form to model a tee 4 feet tall that grows 4 inches each year

SIZIF [17.4K]

Answer:

Y=4x+4

Step-by-step explanation:

if it grows 4 inches each year that means it's the slope

and 4 feet tall model is the y intercept cuz its what you begin with

4 0

2 years ago

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

Which triangles in the diagram are congruent?

GenaCL600 [577]

Answer: triangle 1, triangle 2, and triangle 3

Step-by-step explanation:

Triangles 1 and 3 are congruent by SAS. So, by CPCTC, all three sides are congruent, making triangle 2 congruent to them as well by SSS.

4 0

1 year ago

(N^3 - N^4) - (3n^3- 7n^4)

Free_Kalibri [48]

If you would like to solve (n^3 - n^4) - (3n^3 - 7n^4), you can do this using the following steps:

(n^3 - n^4) - (3n^3 - 7n^4) = <span>n^3 - n^4 - 3n^3 + 7n^4 = n^3 - 3n^3 - n^4 + 7n^4 = -2n^3 + 6n^4
</span>
The correct result would be <span>-2n^3 + 6n^4.</span>

3 0

3 years ago

Can you please answer 8.6 * 7, 16 * 1.4, 12 * 14, 7.3 * 20. altogether 15 points

fenix001 [56]

8.6*7=60.2, 16*1.4=22.4, 12*14=168, 7.3*20=146

7 0

2 years ago

Read 2 more answers