Circle the division problem that does not belong with the other three. Explain 621/6 384/3 719/7 514/5

Mathematics

1 answer:

dsp733 years ago

8 0

384/3. because it comes out even..128..the rest won't

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a. A 2017 poll found that 56% of college students were very confident that their major will lead to a good job. If 15 college s

lesya [120]

Answer:

0.01083 or 1.083%

Step-by-step explanation:

This problem can be modeled as a binomial probability model with probability of success p = 0.56.

The probability of x=13 successes (a college student being very confident their major would lead to a good job) in a number of trials of n=15 is:

$P(X=x) = \frac{n!}{(n-x)!x!} *p^x*(1-p)^{n-x}\\P(X=13) = \frac{15!}{(15-13)!13!} *0.56^{13}*(1-0.56)^{15-13}\\P(X=13) = 0.01083=1.083\%$

The probability is 0.01083 or 1.083%.

8 0

3 years ago

Use calculus to find the largest possible area for a rectangular field that can be enclosed with a fence that is 400 meters long

Setler79 [48]

the largest rectangular area is actually a square.

so the side would be 400/4 = 100 feet

area of a square is S^2

100^2 = 10,000 square feet

6 0

3 years ago

You look at real estate ads for houses in Naples, Florida. There are many houses ranging from $200,000 to $500,00 in price. The

cricket20 [7]

Answer:

c) skewed to the right.

Step-by-step explanation:

We need to remember that is a distribution is skewed to the right then we have the following condition satisfied:

$Mode< Median$

And if is skewed to the left then we have:

$Mean$

If the distribution is symmetric we need to satisfy:

$Mean = Median=Mode$

For this case since we have most of the values between 200000 and 500000 when we put atypical values like 15000000 that would affect the sample mean and on this case the sample mean would larger than the sample median because the median is a robust measure of central tendency not affected by outliers.

So for this special case we can say that the $Mean>Median$ . And probably the median would be higher than the mode so then we can conclude that the best answer for this case would be: