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defon
3 years ago
5

Mason has a collection of 49¢ stamps, 20¢ stamps, and 34 stamps worth $23.55. He has 56 total 49¢ and 20+ stamps and the number

of 3¢ stamps is nine more than the number of 20¢ stamps. How many of each does he have?
Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

Mason has

  • 16 20¢ stamps;
  • 25 3¢ stamps;
  • 40 49¢ stamps.

Step-by-step explanation:

Let x be the number of 20¢ stamps, then the number of 3¢ stamps is  x + 9.

Mason has 56 total 49¢ and 20¢ stamps, then the number of 49¢ stamps is 56 - x.

Amounts:

  • in 49¢: 49(56-x) cents;
  • in 20¢: 20x cents;
  • in 3¢: 3(x+9) cents.

Total amount:

  • 49(56-x)+20x+3(x+9);
  • $23.55.

Hence,

49(56-x)+20x+3(x+9)=2,355\\ \\2,744-49x+20x+3x+27=2,355\\ \\-49x+3x+20x=2,355-2,744-27\\ \\-26x=-416\\ \\26x=416\\ \\x=16

Mason has

  • 16 20¢ stamps;
  • 25 3¢ stamps;
  • 40 49¢ stamps.
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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
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Rationalize the denominator by multiplying both numerator and denominator by √10:

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