Answer:
B. 3x+5−4x=−(x+8)
Step-by-step explanation:pls mark me
Answer:
Step-by-step explanation:
4b + 8 = 20
Subtract 8 from both sides
4b + 8 - 8 = 20 - 8
4b = 12
Now divide both sides by 4
4b/4 = 12/4
b = 3
Check:
LHS = 4b + 8
= 4*3 + 8
= 12 + 8
= 20 = RHS
<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
Answer:
2c^2 - 2c - 3
Step-by-step explanation:
Next time, please share the answer choices. Thank you.
Group together the 'c' terms in 2 + 7c – 4c2 – 3c + 4:
2 + 4c and -4c^2 + 4 Then we have:
-4c^2 + 4c + 6
We should reduce this by factoring -2 out of all three terms:
2c^2 - 2c - 3 This is the desired quadratic in standard form.
Answer:
-sinx
Step-by-step explanation:
a trig identity that is crucial to solving this problem is: sin^2 + cos^2 = 1
with knowing that, you can manipulate that and turn it into 1 - sin^2x = cos^x
so 1-sin^2x/sinx - cscx becomes cos^2x/sinx - cscx
it is also important to know that cscx is the same thing as 1/sinx
knowing this information, cscx can be replaced with 1/sinx
(cos^2x)/(sinx - 1/sinx)
now sinx and 1/sinx do not have the same denominator, so we need to multiply top and bottom of sinx by sinx; it becomes....
cos^2x
---------------------
(sin^2x - 1)/sinx
notice how in the denominator it has sin^2x-1 which is equal to -cos^2x
so now it becomes:
cos^2x
--------------
-cos^2x/sinx
because we have a fraction over a fraction, we need to flip it
cos^2x sinx
---------- * ----------------
1 - cos^2x
because the cos^2x can cancel out, it becomes 1
now the answer is -sinx
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