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3 years ago

I need help on this please some one can help me solve this p4

Mathematics

2 answers:

Scrat [10]3 years ago

7 0

Answer:

d = 10

Step-by-step explanation:

3/4(6 + d) = 12

(18 + 3d)/4 = 12

18 + 3d = 48

3d = 48 - 18

3d = 30

d = 30 : 3

d = 10

AlexFokin [52]3 years ago

4 0

multiple both sides by 4/3

move the constant to the right

subtract the numbers

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What is the length of the hypotenuse? If necessary, round to the nearest tenth.

artcher [175]

Answer:

17 kilometers

Step-by-step explanation:

The pythagorean theorm is a^2 + b^2 = c^2

In this problem we can call 8 km a and 15 km b.

Plug 8 and 15 into the pythagorean theorm to get 8^2 + 15^2 = c^2

This will give you 289=c^2

Take the square root of both sides to get c=17

Hope this helps!

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2 years ago

Read 2 more answers

What is 2\20 divided by 2

Valentin [98]

$\frac{2}{20} \div 2 \\ \\ \frac{1}{10} \div 2 \\ \\ \frac{1}{10} \times \frac{1}{2} \\ \\ \frac{1 \times 1}{10 \times 2} \\ \\ \frac{1}{20} \\ \\$

The final result is: 1/20 or 0.05.

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3 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$