Evaluate int[sin^3(θ)cos(θ)dθ] with u = sin(θ)
du/dθ = cos(θ), dθ = du/cos(θ)

The integral becomes:
int[u^3•cos(θ)du/cos(θ)]
= int[u^3•du]
= u^4/4 + C

Substitute u = sin(θ) to get back a function of θ:
sin^4(θ)/4 + C

3 0

3 years ago

Como se multiplican polinomios

seraphim [82]

I hope you speak english, because although i understood your question I don't know enough spanish to respond in it. You multiply polynomials by multiplying each part of one polynomial by all the other parts of the others, and then adding it all. For example: (ax+b) * (x+c) = (ax*x)+(ax*c)+(b*x)+(b*c) = $a x^{2} + acx + bx+bc$

Comprehende?

7 0

3 years ago

Jose drove 380 miles using 14 gallons of gas. At this rate, how many gallons of gas would he need to drive 418 miles?

PSYCHO15rus [73]

Hey there,
380 miles = 14 gallons
1 miles = 14 / 380
= 7 / 190
418 miles = 7 / 190 x 418
= 15.4 gallons.

Hope this helps :))

~Top

6 0

3 years ago