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sukhopar [10]
3 years ago
10

Raquel throws darts at a coordinate grid centered at the origin. Her goal is to create a line of darts. Her darts actually hit t

he coordinate grid at (–5, 0), (1, –3), (4, 5), (–8, –6), (0, 2), and (9, 6). Which equation best approximates the line of best fit of the darts? y = 0.6x + 0.6 y = 0.1x + 0.8 y = 0.8x + 0.1 y = 0.5x + 0.6

Mathematics
2 answers:
Gnoma [55]3 years ago
8 0
The correct answer is the first option, y = 0.6x + 0.6. When the line of best fit is drawn, the slope can be solved by the formula m=Δy/Δx, where Δy is the difference between two y-coordinates and Δx the difference between two x-coordinates. The y-intercept is the value at which the line coincides with the y-axis (x=0).
34kurt3 years ago
6 0

Solution:

The points at which Raquel Darts hit the coordinate grid having center at the origin are  (–5, 0), (1, –3), (4, 5), (–8, –6), (0, 2), and (9, 6).

As we can see that not all points are collinear.

As line of best fit is the the line which passes through some points , may be not through the single point, or all the points.

Plotting all the options on coordinate grid i.e on a scatter plot and then determining , the  line of best fit of the darts is

y= 0.6 x + 0.6 →→Option (A), the reason being it passes through a point (9,6).

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Evaluate <br> 1/3 ÷ 2/5 =<br> Give your answer as a fraction in its simplest form.
Softa [21]

Answer:

5/6

Step-by-step explanation:

Since 1/3÷2/5 can also be written as 1/3/2/5

So the ÷ can then be converted to × and 2/5 will change to 5/2

So let's solve

1/3×5/2

5/6

Since there is no common number that can divide the two

So the final answer is 5/6

3 0
3 years ago
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Jay just graduated from college and he has decided to open a retirement account that pays 1.75% interest compounded monthly. If
gayaneshka [121]

Answer:

50989.68

Step-by-step explanation:

add 100 to 1.75% then multiply by 12 then multiply by 42

hope that helps :)

4 0
4 years ago
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1/1×3 + 1/3×5 + ... + 1/47×49 HELP PLZ
Natalka [10]

Answer:

  24/49

Step-by-step explanation:

Let's add the terms and see if there's a pattern

  \dfrac{1}{1\times 3}+\dfrac{1}{3\times 5}=\dfrac{5+1}{1\times 3\times 5}=\dfrac{2}{5}\quad\text{sum of 2 terms}\\\\\dfrac{2}{5}+\dfrac{1}{5\times 7}=\dfrac{14+1}{5\times7}=\dfrac{3}{7}\quad\text{sum of 3 terms}

Suppose we say the sum of n terms is (n/(2n+1)), the next term in the series will be 1/((2n+1)(2n+3)) and adding that to the presumed sum gives ...

  \dfrac{n}{2n+1}+\dfrac{1}{(2n+1)(2n+3)}=\dfrac{n(2n+3)+1}{(2n+1)(2n+3)}=\dfrac{2n^2+3n+1}{(2n+1)(2n+3)}\\\\=\dfrac{(2n+1)(n+1)}{(2n+1)(2n+3)}=\dfrac{n+1}{2n+3}\text{ matches }\dfrac{(n+1)}{2(n+1)+1}

Then it appears the sum of n terms is (n/(2n+1)). So, the sum of 24 terms is ...

  S_{24}=\dfrac{24}{2\times24+1}=\boxed{\dfrac{24}{49}}

3 0
3 years ago
Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t
worty [1.4K]

Answer:

a) P(X \leq 100) = 1- e^{-0.01342*100} =0.7387

P(X \leq 200) = 1- e^{-0.01342*200} =0.9317

P(100\leq X \leq 200) = [1- e^{-0.01342*200}]-[1- e^{-0.01342*100}] =0.1930

b) P(X>223.547) = 1-P(X\leq 223.547) = 1-[1- e^{-0.01342*223.547}]=0.0498

c) m = \frac{ln(0.5)}{-0.01342}=51.65

d) a = \frac{ln(0.05)}{-0.01342}=223.23

Step-by-step explanation:

Previous  concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

Solution to the problem

For this case we have that X is represented by the following distribution:

X\sim Exp (\lambda=0.01342)

Is important to remember that th cumulative distribution for X is given by:

F(X) =P(X \leq x) = 1-e^{-\lambda x}

Part a

For this case we want this probability:

P(X \leq 100)

And using the cumulative distribution function we have this:

P(X \leq 100) = 1- e^{-0.01342*100} =0.7387

P(X \leq 200) = 1- e^{-0.01342*200} =0.9317

P(100\leq X \leq 200) = [1- e^{-0.01342*200}]-[1- e^{-0.01342*100}] =0.1930

Part b

Since we want the probability that the man exceeds the mean by more than 2 deviations

For this case the mean is given by:

\mu = \frac{1}{\lambda}=\frac{1}{0.01342}= 74.516

And by properties the deviation is the same value \sigma = 74.516

So then 2 deviations correspond to 2*74.516=149.03

And the want this probability:

P(X > 74.516+149.03) = P(X>223.547)

And we can find this probability using the complement rule:

P(X>223.547) = 1-P(X\leq 223.547) = 1-[1- e^{-0.01342*223.547}]=0.0498

Part c

For the median we need to find a value of m such that:

P(X \leq m) = 0.5

If we use the cumulative distribution function we got:

1-e^{-0.01342 m} =0.5

And if we solve for m we got this:

0.5 = e^{-0.01342 m}

If we apply natural log on both sides we got:

ln(0.5) = -0.01342 m

m = \frac{ln(0.5)}{-0.01342}=51.65

Part d

For this case we have this equation:

P(X\leq a) = 0.95

If we apply the cumulative distribution function we got:

1-e^{-0.01342*a} =0.95

If w solve for a we can do this:

0.05= e^{-0.01342 a}

Using natural log on btoh sides we got:

ln(0.05) = -0.01342 a

a = \frac{ln(0.05)}{-0.01342}=223.23

5 0
3 years ago
There are 4 sports stores,9 clothing stores and 6 jewelry stores ina shopping crnter which ratio compares the number of sports s
Pani-rosa [81]

The ratio is  2 : 9

Step-by-step explanation:

Given:

The number of sports store = 4

The number of clothing store  = 9

The number of jewellery stores = 5

To Find :

The ratio of number of sports stores to the total number of stores

Solution:

The ratio of number of sports stores to the total number of stores

= \frac{\text{number of sports store}}{\text{ Total number of stores}}

The total number of stores =  number of sports store + number of clothing store + number of jewellery store

The total number of stores = 4 + 9 + 5

The total number of stores = 18

Now the ratio is

= \frac{4}{18}   or 4  :  8

The ratio after reduction is

=\frac{2}{9} or 2 : 9  or   2 to 9

7 0
4 years ago
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