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Artyom0805 [142]
3 years ago
12

sam correctly answered 80 of the questions on his last math test if he missed 3 problems how many questions were on the test

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0
If sam correctly answered 80 of the questions on his last math test but missed 3 problems, there was 83 questions on the test.

80 + 3 = 83

God bless!
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Victor has saved $89.25 for the bicycle that he wants. The bicycle costs $129.85. Victor
serious [3.7K]

Answer:

Victor's equation did not correctly model the problem.

The equation that correctly modeled the problem:

$129.85-$89.25=$40.60

Step-by-step explanation:

The amount required for bicycle purchase by Victor is $129.85 out of which $89.25 has been saved,in other words,the balance required for Victor to reach his target purchase price is the difference between the total cost of $129.85 and the $89.25 already saved.

The balance required=$129.85-$89.25=$40.6

This shows that the equation put forward by Victor is wrong.

An equation that correctly represents the problem is the difference between the target savings and the amount already saved as stated above

5 0
3 years ago
3(x - 4) + 8(x + 2).
FromTheMoon [43]
3(x - 4) + 8(x + 2) = 3x - 12 + 8x + 16 = 11x + 4
3 0
3 years ago
I don’t really understand this may you please help!¡
Helga [31]

Answer:(15+6)÷3


Step-by-step explanation:

You add 15 and 6 to get the total, the divide by 3 to see how much each person pays.


7 0
3 years ago
-1x + 4y &lt;4<br> how to slove this
vazorg [7]

Answer: y = 1/4x + 1

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6 0
3 years ago
Suppose you can afford only $200 a month in car payments and your best loan option is a 60-month loan at 3%. How much money coul
g100num [7]

Answer:

  $11,130.47

Step-by-step explanation:

The amortization formula can be used. It tells you the monthly payment amount A for some principal P, interest rate r, and n payments.

  A = P(r/12)/(1 -(1 +r/12)^(-n))

Filling in your values, we get ...

  200 = P(.03/12)/(1 -(1 +.03/12)^-60) = P(.0025)/(1 -1.0025^-60)

  P = 200(1 -1.0025^-60)/.0025 ≈ 200×55.6523577

  P ≈ 11,130.47

The present value of the loan is $11,130.47.

8 0
3 years ago
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