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vivado [14]
3 years ago
12

Choose the graph that matches the following system of equations:

Mathematics
1 answer:
Lelu [443]3 years ago
4 0
In intercept form, the equations are
.. x/(-5/8) +y/(-1) = 1
.. x/(3/7) +y/(-1) = 1

The first line has intercepts (-5/8, 0) and (0, -1).
The second line has intercepts (3/7, 0) and (0, -1)

In the second graph, the (blue) line with positive slope has an x-intercept greater than 1/2. Neither line matches that. The intercepts match those of the first graph.
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Simplify (2m^6)^3.
labwork [276]

Answer:

B. 8m ^ 18

Step-by-step explanation:

(2m ^6)^3 is the same as ;

(2 ^1 × m ^ 6) ^ 3.....multiply the powers 1 and 6 by 3

2 ^ (1×3) × m ^ (6×3).....this equals;

2 ^ 3 × m ^ 18

8m^18

hope this helps :)

8 0
3 years ago
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Find area of the circle
noname [10]
37.68 is the answer

Hope this helped! ^_^
4 0
3 years ago
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Helppp pleaseee if you can !!! if you can’t see the pic don’t bother answering
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Answer:

D. $ 650

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4 0
3 years ago
Calculating cos-1 ( help is gladly appreciated :) )
Alekssandra [29.7K]

Answer:

\frac{3\pi}{4}

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by \frac{180^\circ}{\pi} giving you:

\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}.

We can do this since \pi \text{ rad }=180^\circ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

\cos^{-1}(x) is going to output an angle measurement in [0,\pi].

So we are looking to solve the following equation in that interval:

\cos(x)=-\frac{\sqrt{2}}{2}.

This happens in the second quadrant on the given interval.

The solution to the equation is \frac{3\pi}{4}.

So we are saying that \cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2} implies \cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4} since \frac{3\pi}{4} \in [0,\pi].

Answer is \frac{3\pi}{4}.

4 0
3 years ago
Drag expressions to complete each equation.
irga5000 [103]

Answer:

1st one a^-1 , 2nd one a^b/a^c , 3rd one a^c/b^c

8 0
3 years ago
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