Question

A rock falls for 1.43 seconds how far did it fall? The falls's velocity is an acceleration of -9.81 m/s2

Answer 1

Answer:

$s = -0.100 \ m$

Explanation:

Generally from kinematics equations we have that

          $s = ut + \frac{1}{2}gt^2$

Here u is the initial velocity of the rock and the value is  0 m/s given that there was no information that it was in motion before the fall

substituting 1.43 s for t and $-9.8m/s^2$ for g we have that

         $s = 0 *1.43 + \frac{1}{2}(-9.8)*(0.143)^2$

=>     $s = -0.100 \ m$

The negative sign show that the displacement is in the direction of the negative y-axis