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daser333 [38]
3 years ago
14

As an electric current flows through the copper sulfate solution, copper settles on the negative electrode. How will the mass of

the copper covering this electrode change if we increase the current by 4 times and halve its flow time?
Physics
1 answer:
andrezito [222]3 years ago
4 0

Answer:

Ține ogaru ca să o lingă pe măta în cur să nu mai facă alt prost ca tine

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Explanation:

R = R ref ( 1 + ∝ ( T - Tref)  

where R = conduction resistance at temperature T

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T ref = reference temperature that ∝ is specified at for the conductor material

T = 600 k - 273 k = 327 °C

Tref = 300 - 273 K = 27 °C

R = 50 Ω ( 1 + 0.007 ( 327 - 27) )

R = 155Ω

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