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dimaraw [331]
4 years ago
15

Which of the following shows 9x2y - 4x + 3y3x - 2y2 written in standard form?

Mathematics
2 answers:
prohojiy [21]4 years ago
8 0

Answer:

the answer is D.

Step-by-step explanation:

Bad White [126]4 years ago
6 0

Answer:

option (4) is correct.

the given expression 9x^2y-4x+3y^3x-2y^2  can be written in standard form as 3y^3x+9x^2y-2y^2-4x.

Step-by-step explanation:

The Standard form of writing an equation,  

1) Look at the degree of each term.

2)  You then write each term in order of degree, from highest to lowest, left to right..

3) The expression x^2y has an exponent of 2 on the x and an unwritten exponent of 1 on the y, so this term is to the third degree (2+1). We add the two degrees together because it has two variables.

Consider the given equation,

9x^2y-4x+3y^3x-2y^2

We have to write it in  standard form using the steps stated above,

first we find the degree of each term in the given expression,

The expression x^2y has an exponent of 2 on the x and an unwritten exponent of 1 on the y, so this term is to the third degree (2+1).

The expression y^3x has an exponent of 3 on the y and an unwritten exponent of 1 on the x, so this term is to the third degree (3+1).

So the highest degree in the given expression is  3y^3x

write each term in order of degree, from highest to lowest, left to right.

following this , we can write the expression as,

3y^3x+9x^2y-2y^2-4x

Thus, option (4) is correct.




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The axis of symmetry for the function f(x) = –2x2 + 4x + 1 is the line x = 1. Where is the vertex of the function located?
egoroff_w [7]

Answer:

(1, 3)

Step-by-step explanation:

You are given the h coordinate of the vertex as 1, but in order to find the k coordinate, you have to complete the square on the parabola.  The first few steps are as follows.  Set the parabola equal to 0 so you can solve for the vertex.  Separate the x terms from the constant by moving the constant to the other side of the equals sign.  The coefficient HAS to be a +1 (ours is a -2 so we have to factor it out).  Let's start there.  The first 2 steps result in this polynomial:

-2x^2+4x=-1.  Now we factor out the -2:

-2(x^2-2x)=-1.  Now we complete the square.  This process is to take half the linear term, square it, and add it to both sides.  Our linear term is 2x.  Half of 2 is 1, and 1 squared is 1.  We add 1 into the set of parenthesis.  But we actually added into the parenthesis is +1(-2).  The -2 out front is a multiplier and we cannot ignore it.  Adding in to both sides looks like this:

-2(x^2-2x+1)=-1-2.  Simplifying gives us this:

-2(x^2-2x+1)=-3

On the left we have created a perfect square binomial which reflects the h coordinate of the vertex.  Stating this binomial and moving the -3 over by addition and setting the polynomial equal to y:

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From this form,

y=-a(x-h)^2+k

you can determine the coordinates of the vertex to be (1, 3)

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In this question:

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