Answer:
Step-by-step explanation:
Subtract the 4 from 9
Since it's a sample size, we use x, as the mean and s= standard deviation
_
Given: x =27, s = 2 and total sample = 32.
Probability that a recruit is at least 31 years old?
Let's calculate the Z score :
_
X - x 31 - 27
Z = ----------- → Z = -------- → Z = 2 (now look up in the Z score table,
s 2
Area (Z=2) =0.9772 , but Z ≥ 2 (at least) , then :
Area (Z≥2) = Area (Z≤ - 2) = 0.0228
P(≥31)= 0.0228
Answer:
no solution
Step-by-step explanation:
hello
this is always false so there is no solution
180÷(300-30)×9+199
180 ÷ (270)×9+199
180÷270=
.66×9=
5.94+199=
204.94, approximately 205
