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LenaWriter [7]
3 years ago
10

Use properties to find the sum of product 8×51gb

Mathematics
1 answer:
Eddi Din [679]3 years ago
5 0

8(51) = 8(50 + 1) = 8(50) + 8(1) = 400 + 8 = 408

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I need help in math please I am not able to figure these out, I will give you the brainlest and thank you.
saul85 [17]

Answer:

A. -7 A2. -7

B.-14 B2. 2

C.-14 C2.14

D. 1 D2. -7

3 0
3 years ago
Solve the inequality - 4x+5&gt;-5<br><br> x &lt; 2.5<br> x &gt; -2.5<br> x &gt; 2.5
GalinKa [24]

Answer:

- 4x >  - 10 \\ x < 2.5

4 0
3 years ago
Which equation represents this sentence?
Oduvanchick [21]
It should be n+4=3n. Hope this helps
3 0
2 years ago
What is 11+23/60 as a mixed number
hodyreva [135]

Answer:

the answer is 683/60

Step-by-step explanation:

just multiply 60 by 11 then add 23, or multiply the bottom number by the whole number then add the top number

3 0
3 years ago
Please solve the following question.
mylen [45]

Answer:

103, 776

Step-by-step explanation:

There are 48 possibilities, and you are picking 3.

Now, the order does matter (aka, if the same 3 athletes won but got different places, we would still consider it to be a separate possibility)

(this is considered "without repetitions")

the number of permutations (arrangement combinations where the order does matter) without repetitions formula:

Number of permutations

without <em>repetitions </em>= nPr

= \frac{n!}{(n-r)!}

(

[the P is for combinations [where the order does matter, if the order didn't matter then it would be C, and it would be a different formula.]

n is the total number of objects.

r is the number of objects selected]

<em>(a repetition would be like two versions of the same person competing, which doesn't make sense)</em>

{the ! means factorial:

5! = 5 x 4 x 3 x 2 x 1}

{for example, if there are 5 people to give a presentation, and they can go in any order [but cannot repeat their presentation], so they all must fill 5 slots}

{for the first slot there are 5 choices, the second slot there are 4 choices...}

)

So, if we follow this formula:

\frac{n!}{(n-r)!}

n: 48

r: 3

\frac{48!}{(48-3)!}

= \frac{48!}{45!}

=\frac{48 * 47*46*45!}{45!}

(the 45! cancel out)

= 48 * 47 * 46

= 103, 776

(or, without the formula:

for the first choice (lets say of gold), there are 48 options

for the second choice (lets say silver), there are 47 options left to choose from

for the third choice (lets say bronze), there are 46 options left to choose from

)

3 0
2 years ago
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