1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DiKsa [7]
3 years ago
5

BeWhat direction do you predict the addition of a base to the solution containing bromophenol blue will drive the equilibrium? E

xplain your prediction in terms of le chatelier principle

Chemistry
1 answer:
klasskru [66]3 years ago
8 0

Answer:

Explanation:

Le Chatlier's principle expresses that when a system in equilibrium is irritated by outside changes, the system reacts by altering the equilibrium concentrations of its segments to such an extent that the annoyance is invalidated and accomplishes an equilibrium state at this bothered condition, with equilibrium concentrations not quite the same as in the past.

Bromothymol blue is a phenolic suflone that demonstrations a weak acid in aqueous media. Being a weak acid, it doesn't ionize totally and builds up a harmony with its related and separated structure.

From Le Chatlier's guideline, it very well may be found out that when a strong acid is included, the last's finished separation, without foundation of equilibrium causes a spike in the proton concentration in the medium. This expansion in proton concentration is the outer bother and the framework will react by shifting to one side, consequently protonating more dianions of bromothymol with an end goal to invalidate the proton concentration increment.  

Thus, when a base is included, it devours the protons in the medium to shape water. In this way, the concentration of protons in the medium declines. To repay this change, the equilibrium reacts by shifting to the privilege i.e., it makes a greater amount of the unbiased pointer separate into the dianion and protons, hence endeavors to invalidate the bother.

You might be interested in
A sample of limestone (calcium carbonate, CaCO3) is heated at 950 K until it is completely converted to calcium oxide (CaO) and
pav-90 [236]

Answer:

Therefore, volume of CO₂ produced in the first step is 9141.404 L

Explanation:

Equations of reactions:

A: CaCO₃(s) ---> CaO(s) + CO₂(g)

B: CaO(l) + H₂O(l) ---> Ca(OH)₂(s)

Molar mass of CaCO₃ = 100 g; molar mass of CaO = 56 g; molar mass of CO₂ = 44 g molar mass of H₂P = 18 g; molar mass of Ca(OH)₂ = 74 g

From equation B, 1 mole of CaO produces 1 mole of Ca(OH)₂

This means that 56 g of CaO produces 74 g of Ca(OH)₂

mass of CaO that produces 8.47 kg or 8470 g of Ca(OH)₂ = 8470 g * 56/74 = 6409.73 g of CaO

Therefore, 6409.73 g of CaO were produced in reaction A

From reaction A, 1 mole of CaCO₃ produces 1 mole CaO and 1 mole of CO₂

Number of moles of CaO in 6409.73 g = 6409.73 g/56 g/mol = 114.46 moles

Therefore, 114.46 moles of CO₂ were produces as well.

Molar volume of gas at STP = 22.4 litres

Volume of CO₂ produced at STP = 114.46 * 22.4 L =2563.904 L

However, the above reaction took place at 950 K and 0.976 atm, therefore volume of CO₂ produced under these conditions are obtained using the general gas equation

Using P₁V₁/T₁ = P₂V₂/T₂

P₁ = 1.0 atm, V₁ = 2563.904 L, T₁ = 273 K, P₂ = 0.976 atm, T₂ = 950 K, V₂ = ?

V₂ = P₁V₁T₂/P₂T₁

V₂ = (1.0 * 2563.904 * 950)/(0.976 * 273)

V₂ = 9141.404 L

Therefore, volume of CO₂ produced in the first step is 9141.404 L

3 0
3 years ago
1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium
lilavasa [31]

Answer:

This question is incomplete, here's the complete question:

1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium ion present in 20.0 mL of each buffer.

Buffer A

Mass of sodium acetate used: 0.3730 g

Actual ph of the buffer 5.27

volume of the buffer used in buffer capacity titration 20.0 mL

Concentration of standardized NaOH 0.100M

moles of Naoh needed to change the ph by 1 unit for the buffer 0.00095mol

the buffer capacity 0.0475 M

Buffer B

Mass of sodium acetate used 1.12 g

Actual pH of the buffer 5.34

Volume of the buffer used in buffer capacity titration 20.0 mL

Concentration if standardized NaOH 0.100 M

moles of Naoh needed to change the ph by 1 unit 0.0019 mol

the buffer capacity 0.095 M

2.) A change of pH by 1 unit means a change in hydronium ion concentration by a factor of 10. Calculate the number of moles of NaOH that would theoretically be needed to decrease the moles of hydronium you calculated in #1 by a factor of 10 for each buffer. Are there any differences between your experimental results and the theoretical calculation?

3.) which buffer had a higher buffer capacity? Why?

Explanation:

Formula,

moles = grams/molar mass

molarity = moles/L of solution

1. Buffer A

molarity of NaC2H3O2 = 0.3731 g/82.03 g/mol x 0.02 L = 0.23 M

molarity of HC2H3O2 = 0. 1 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.23/0.1)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

Buffer B

molarity of NaC2H3O2 = 1.12 g/82.03 g/mol x 0.02 L = 0.68 M

molarity of HC2H3O2 = 0.3 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.68/0.3)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

2. let x moles of NaOH is added,

Buffer A,

pH = 5.10

[H3O+] = 7.91 x 10^-6 M

new pH = 4.10

new [H3O+] = 7.91 x 10^-5 M

moles of NaOH to be added = (7.91 x 10^-5 - 7.91 x 10^-6) x 0.02 L

= 1.42 x 10^-6 mol

3. Buffer B with greater concentration of NaC2H3O2 and HC2H3O2 has higher buffer capacity as it resists pH change to a wider range due to addition of acid or base to the system as compared to low concentration of Buffer A

5 0
3 years ago
Please help fast<br>I WILL MARK YOU AS BRAINLIEST ​
Elan Coil [88]

Answer:

c

Explanation:

all the atoms must be balanced.

3 0
3 years ago
Severus Snape explains that if you have the molar mass of a compound and the empirical formula of a compound you can determine t
KengaRu [80]

Answer:

The molecular formula of the compound :C_4H_6O_2

Explanation:

The empirical formula of the compound =C_2H_3O

The molecular formula of the compound =C_{2n}H_{3n}O_n

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 86 g/mol

Mass of empirical formula = 43 g/mol

Putting values in above equation, we get:

n=\frac{86g/mol}{43g/mol}=2

The molecular formula of the compound :

C_{2\times 2}H_{3\times 2}O_2=C_4H_6O_2

7 0
3 years ago
1. When this equation is balanced, Fe + 02 -.--&gt; Fe203, what is the
Vilka [71]

Fe + O2 → Fe2O3

After balancing the eq.

4Fe + 3O2 → 2Fe2O3

Hope this will help u mate :)

4 0
4 years ago
Other questions:
  • Compared to 1 liter aqueous solution with a ph of 7, a 1 liter aqueous solution with a ph of 5.0 contains
    9·1 answer
  • Calculate the average mass for iron. 15.2% iron-55, 85.8% iron-56
    7·1 answer
  • ??????????????????????????????
    10·1 answer
  • Sodium-24 has a half life how much sodium-24 will remain in an 18 g sample after 75 hours
    15·1 answer
  • Whose personal story did you read (if you read several, pick your favorite)? What was the most interesting or eye-opening part o
    7·1 answer
  • At what celcius temperature does 0.750 mol of an ideal gas occupy a volume of 35.9 L at 114 kPa
    5·1 answer
  • The moons appearance from the earth changes throughout its orbital path because the amount of .... varies ?
    15·1 answer
  • A student says: Potassium (K) always has 20 protons. Explain why the student is incorrect.
    15·1 answer
  • Evidence of chemical reactions include changes in
    5·1 answer
  • Matter cannot be created or __________.
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!