1.d
2.g
3.j
4.i
5.c
6.h
7.e
8.b
9.a
10.f
Answer:
4,38%
small molecular volumes
Decrease
Explanation:
The percent difference between the ideal and real gas is:
(47,8atm - 45,7 atm) / 47,8 atm × 100 = 4,39% ≈ <em>4,38%</em>
This difference is considered significant, and is best explained because argon atoms have relatively <em>small molecular volumes. </em>That produce an increasing in intermolecular forces deviating the system of ideal gas behavior.
Therefore, an increasing in volume will produce an ideal gas behavior. Thus:
If the volume of the container were increased to 2.00 L, you would expect the percent difference between the ideal and real gas to <em>decrease</em>
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I hope it helps!
Answer:
{1s^2 2s^2 2p^6} 3s^2 3p^4
{Ne}3s^2 3p^4
Explanation:
i didnt understand the rest of that but this is the e- configuration on top and the bottom is noble gas configuration
H2O is the chemical formula of water. It means that each molecule of water is made up of two hydrogen atoms, indicated by the letter H, and a single oxygen atom, represented by the O. Water is a chemical substance with no smell, taste, or color.
Answer:
a) 6.5
b) pressure decreases
c)22 atm
Explanation:
Since the initial volume V1 is 5.40 L and the final volume V2 is 35.1 L, the ratio of V2:V1= 35.1/5.40= 6.5 hence the volume increases by a factor of 6.5.
When the volume increases, the pressure decreases accordingly in accordance with Boyle's law. Boyle's law states that the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.
c) From Boyle's law
Initial volume V1= 5.40 L
Final volume V2= 35.1 L
Initial pressure P1= 143 ATM
Final pressure P2 = the unknown
P1V1= P2V2
P2= P1V1/V2
P2 = 143 × 5.40/ 35.1
P2= 22 atm
