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Alla [95]
3 years ago
15

You are traveling in a convertible with the top down. The car is moving at a constant velocity 28.9 m/s, due east along flat gro

und. You throw a tomato straight upward at a speed of 15.6 m/s. How far has the car moved when you get a chance to catch the tomato?
Physics
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

91.914138 m

Explanation:

t = Time taken

u = Initial velocity = 15.6 m/s

v = Final velocity = -15.6 m/s (it will hit the ground at this speed)

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{-15.6-15.6}{-9.81}\\\Rightarrow t=3.18042\ s

Distance=Speed\times Time

d=3.18042\times 28.9\\\Rightarrow d=91.914138\ m

The distance the car will travel is 91.914138 m

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What causes air to become less dense and rise?
aalyn [17]

Answer:

That force is 'gravity'.

8 0
4 years ago
This problem has been solved!
RideAnS [48]

Answer:

Option (a)

Explanation:

We will discard options that don't fit the situation:

Option b: <em>Incorrect </em>since if the driver "hits the gas" then velocity is augmenting and it's not constant.

Option c and d: <em>Incorrect </em>since the situation doesn't give us any information that could be related directly to the terrain or movement direction.

Option a: Correct. At <em>stage 1</em> we can assume the driver was going at constant speed which means acceleration is constantly zero. At <em>stage 2 </em>we can assume the driver augmented speed linearly, this is, with constant positive acceleration. At <em>stage 3 </em>we can assume the driver slowed the speed linearly, with constant negative acceleration.

6 0
3 years ago
A constant torque is applied to a rigid wheel whose moment of inertia is 2.0 kg · m2 around the axis of rotation. If the wheel s
Jlenok [28]

Answer:

The applied torque is 3.84 N-m.      

Explanation:

Given that,

Moment of inertia of the wheel is 2\ kg-m^2

Initial speed of the wheel is 0 (at rest)

Final angular speed is 25 rad/s

Time, t = 13 s

The relation between moment of inertia and torque is given by :

\tau=I\alpha \\\\\tau=I\times \dfrac{\omega_f}{t}\\\\\tau=2\times \dfrac{25}{13}\\\\\tau=+3.84\ N-m

So, the applied torque is 3.84 N-m.

4 0
3 years ago
What is the momentum of a bowling ball with mass of 8.9 kg and a speed of 6.0 m / s
PtichkaEL [24]

Answer:

The momentum of the bowling ball is 53.4 kg-m/s.

Explanation:

We have,

Mass of a bowling ball is 8.9 kg

Speed of the ball is 6 m/s

It is required to find the momentum of the ball. The momentum of an object is given in terms of its mass and speed as :

p = mv

p=8.9\times 6\\\\p=53.4\ kg-m/s

So, the momentum of the bowling ball is 53.4 kg-m/s.

7 0
4 years ago
Which of the following equations should be used to find the minimum thickness t of the oil film that satisfies the conditions of
Sergeeva-Olga [200]

Answer:

The equations are:

C. 2t=(m+12)λn(m=0,1,2,...) for constructive interference. (Here is a mistake in this equation i.e. m + 12 (wrong) and m + 1/2 (correct)). So, the correct equation for constructive interference is:

2t = (m + 1/2) λ n (m=0,1,2,...)  

D. 2t=mλn(m=0,1,2,...) for destructive interference.

Explanation:

Constructive Interference occurs when two waves’ crests or troughs add together therefore, the resulting wave amplitude is equal to the sum of the each wave amplitude (in this case the amplitude of each wave is of same charge).

Destructive Interference occurs when a waves’ crest and trough cancel each other therefore, the resulting wave amplitude is zero (in this case the amplitude of each wave is oppositely charged).

When the refractive index of the medium in which the light travels is lower than the refractive index of the thin film medium then a 180° phase shift occurs.

When the light wave strikes the top surface of thin film, the wave reflects from the top surface and the reflecting light wave shifts by half of wavelength i.e. λ/2

When the light wave strikes the bottom surface of thin film then the light wave does not shift however, the light cover extra distance (2t), reflecting from the bottom surface to travel back to air.

Since, oil has refractive index (n = 1.5) which is higher than the refractive index of air (n = 1) so, when light wave strikes on the top surface of thin film of oil, the reflecting wave will shift by λ/2 (because nair < noil) and when light wave strikes on the bottom surface of thin film of oil, it will cover an extra distance to travel back to air and no wavelength shift will occur (because noil > nair).

In light of the above situation, the constructive interference of light reflected from the thin oil film is:

2t = (m + 1/2) λ n  

The destructive interference of light reflected from the thin film is:  

2t = m λ n

3 0
4 years ago
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