Earth's surface receives about twice as much energy from the atmosphere than from the sun as a result of ___

After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average

alexira [117]

Answer:

Incomplete Question

Explanation:

String constant is not stated

I'll solve this in a general way.

At the end of my explanation, I'll assume any value for string constant.

The total weight on the taptap : Weight of people + Weight of goats + Weight of chickens + weight of banana

= (25 * 66) + (3 * 15) + (5 * 3) + 25 = 1735 kg

The gravitational force exerted on the taptap

Fig = m*g

where m = the total mass 1735kg

and g = 9.8m/s²

Hooke's law of Elasticity states that

Fs = Kx

Where Fs = spring force

k = spring constant

x = spring stretch or compression

Since Fs = Fg

So, Kx = mg

Make x the subject of the formula

x = mg/k --------------- This is the general way of solving for spring compressor in cases like this

I'll replace m and g with their values, respectively.

Because, the spring constant (k) is omitted in the question, I'll assume it to be 30000

x = 1735 * 9.8/30000

x = 17003/30000

x = 0.566767 metres

x = 0.57 metres ------------- Approximated

In conclusion, the spring compression is 0.57 metres if the spring constant is 30000

6 0

3 years ago

If you planned to bike to a park that was five miles away, what average speed would you have to maintain to arrive in about 15 m

AfilCa [17]

The average speed you need to maintain is 0.33 miles per minute.

The average speed is the speed that you maintain throughout the journey. It is obtained as; Total distance covered/Total time taken

If we have the following information from the question;

Distance covered = 5 miles

Time taken = 15 mins

Then it follows that;

Average speed = Distance/time

Average speed= 5 miles/15mins

Average speed = 0.33 miles per minute.

Learn more: brainly.com/question/17661499

5 0

3 years ago

A boy whirls a stone in a horizontal circle of radius 1.8 m and at height 1.8 m above level ground. The string breaks, and the s

umka2103 [35]

Answer:

Acceleration is $148.33\ m/s^{2}$

Solution:

As per the question:

Radius of the circle, R = 1.8 m

Height above the ground, h = 1.8 m

Horizontal distance, x = 9.9 m

Now,

The magnitude of the centripetal acceleration can be calculated as:

$a_{c} = \frac{v^{2}}{R}$

where

v = velocity

R = radius

$a_{c}$ = centripetal acceleration

Now, if we consider the vertical component of motion only, then considering the initial velocity, 'u' = 0, from kinematic eqn:

$h = ut + \frac{1}{2}gt^{2}$

$h = 0.t + \frac{1}{2}gt^{2}$

$t = \sqrt{\frac{2h}{g}}$

$t = \sqrt{\frac{2\times 1.8}{9.8}}$

t = 0.606 s

Now, for the horizontal component of velocity:

x = vt

$v =\frac{x}{t}$

$v =\frac{9.9}{0.606} = 16.34\ s$

Now, we know that the centripetal acceleration is given by:

$a_{c} = \frac{16.34^{2}}{1.8} = 148.33\ m/s^{2}$

6 0

3 years ago

How many covalent bonds can be formed by Nitrogen? Please explain

natka813 [3]

Three bonds

<span>Here are the combinations of hydrogen with boron, carbon, nitrogen, oxygen and fluorine. Generally to complete an octet Group 4A will form four bonds, Group 5A will form 3 bonds, Group 6A will form 2 bonds, etc. Three bonds: Boron is in group 3A. It has three valence electrons.</span>

6 0

3 years ago

If we are to expand the exploration of our solar system our next manned flight should be to Phobos, one of Mars's moons, rather

SIZIF [17.4K]

Answer:

E - Lift-off for the return trip from Phobos requires much less fuel than that from Mars because of Phobos weaker gravitational pull.

Explanation:

Fuel requirement might be lesser in case of Phobos expedition.

This explains the fact that fuel consumption during lift off from Phobos is greater than the fuel consumption during lift off from Mars. Therefore E is the best answer.

6 0

4 years ago

Earth's surface receives about twice as much energy from the atmosphere than from the sun as a result of ____.