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padilas [110]
3 years ago
5

Earth's surface receives about twice as much energy from the atmosphere than from the sun as a result of ____.

Physics
1 answer:
Oxana [17]3 years ago
5 0
I think the answer is “greenhouse effect”
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The conservation laws, show ift<br>te-te​
FinnZ [79.3K]

Answer:

Explanation:

In physics, a conservation law states that a particular measurable property of an isolated physical system does not change as the system evolves over time. The exact conservation laws include conservation of energy, and conservation of linear momentum, and also conservation of angular momentum, aswell as the conservation of electric charge

7 0
3 years ago
Climate change is causing the average annual temperature to increase. Birds that have adapted to temperatures in their environme
Luba_88 [7]
Are their any multiple choice questions? Also you said, "<span>Birds that have adapted to temperatures in their environment must find a way to adapt." It says they already adapted lol</span>
4 0
3 years ago
Read 2 more answers
A generator is designed to produce a maximum emf of 190 V while rotating with an angular speed of 3800 rpm. Each coil of the gen
Zinaida [17]

Answer:

The number of turns of wire needed is 573.8 turns

Explanation:

Given;

maximum emf of the generator, = 190 V

angular speed of the generator, ω = 3800 rev/min =

area of the coil, A = 0.016 m²

magnetic field, B = 0.052 T

The number of turns of the generator is calculated as;

emf = NABω

where;

N is the number of turns

\omega = 3800 \frac{rev}{min} \times \frac{2\pi}{1 \ rev} \times \frac{1 \min}{60 \ s } = 397.99 \ rad/s

N = \frac{emf}{AB\omega } \\\\N = \frac{190}{0.016 \times 0.052\times 397.99} \\\\N = 573.8 \ turns

Therefore, the number of turns of wire needed is 573.8 turns

4 0
3 years ago
A circular loop of wire with a diameter of 0.626 m is rotated in a uniform electric field to a position where the electric flux
Mila [183]

Answer:

C) 2.44 × 106 N/C

Explanation:

The electric flux through a circular loop of wire is given by

\Phi = EA cos \theta

where

E is the electric field

A is the cross-sectional area

\theta is the angle between the direction of the electric field and the normal to A

The flux is maximum when \theta=0^{\circ}, so we are in this situation and therefore cos \theta =1, so we can write

\Phi = EA

Here we have:

\Phi = 7.50\cdot 10^5 N/m^2 C is the flux

d = 0.626 m is the diameter of the coil, so the radius is

r = 0.313 m

and so the area is

A=\pi r^2 = \pi (0.313 m)^2=0.308 m^2

And so, we can find the magnitude of the electric field:

E=\frac{\Phi}{A}=\frac{7.50\cdot 10^5 Nm^2/C}{0.308 m^2}=2.44\cdot 10^6 N/C

3 0
3 years ago
What happens to parallel light rays that strike a concave lens?
torisob [31]

Answer:

They diverge on refraction

Explanation:

When parallel light rays strike a concave lens, they will diverge that is they spread out .

Concave lens is also known as diverging lens, which means that when parallel rays of light strike on it, the lens spreads out the light rays ( that is it diverges the rays of light) that are refracted through it.

At the middle  of concave lens is thinner.  

When light is passes through the lens they diverge it or spread out.

The concave lens causes light rays to bend away or diverge from its axis since the concave lens is a diverging lens.  

5 0
3 years ago
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