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Ede4ka [16]
3 years ago
10

What makes conductors conductors?

Physics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:

"Conductor" implies that the outer electrons of the atoms are loosely bound and free to move through the material.

Explanation:

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a baseball is hit straight up into the air. If the initial velocity was 20 m/s, how high will the ball go?How long will it be un
AleksAgata [21]
1) The motion of the ball is an uniformly accelerated motion, with constant acceleration equal to g=-10 m/s^2 (the negative sign means it is directed towards the ground).

For an uniformly accelerated motion, we can use the following relationship:
2gh=v_f^2-v_i^2
where h is the maximum height reached by the ball, v_i = 20 m/s is its initial velocity and v_f the velocity of the ball when it reaches the maximum height. But v_f=0 (when the ball reaches the maximum height, it stops before going down, so its velocity at that moment is zero), so we can use the relationship to  calculate h, the maximum height:
h=- \frac{v_i^2}{2g} =- \frac{20 m/s)^2}{2 \cdot (-10 m/s^2)} =20 m

2) We can find the time the ball takes to return to the ground by requiring that the space covered by the ball returns to zero: 
S(t)=0
where for an uniformly accelerated motion,
S(t)=v_i t +  \frac{1}{2} gt^2 =0
By solving this, we have two solutions: one is t=0, which corresponds to the moment the player hits the ball, the second one is
t=- \frac{2 v_i}{g}=- \frac{2 \cdot 20 m/s}{-10 m/s^2}=4 s
so, the ball returns to the ground after 4 s.

3) The velocity of the ball when it returns to the ground is given by:
v(t) = v_i +gt=20 m/s + (-10 m/s^2)(4 s)=-20 m/s
where the negative sign means the ball is going downwards.
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3 years ago
Why don't you notice your gravitational force on other objects?
mixas84 [53]
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4 0
3 years ago
Read 2 more answers
Fifteen identical particles have various speeds: one has a speed of 2.00 m/s, two have speeds of 3.00 m/s, three have speeds of
Evgesh-ka [11]

Answer:

a)  V=7.5m/s

b) rms=8.4m/s

c) Generally the most probable speed is 8m/s as it the most posses by particles being the average

Explanation:

From the question we are told that:

Sample size N=15

  Speed 1 v_1=2m/s\\\\Speed 2 v_2=3m/s\\\\Speed 3 v_2=5m/s\\\\Speed 4 v_4=8m/s\\\\Speed 3 v_5=9m/s\\\\Speed 2 v_6=15m/s\\\\

Generally the equation for Average speed is mathematically given by

 V_{avg}=\frac{\sum(nv)}{N}

Therefore

 V_{avg}=\frac{(2+2(3)+3(5)+4(8)+3(9)+2(15))}{15}

 V=7.5m/s

b)

Generally the equation for RMS speed of the particle is mathematically given by

  rms=\sqrt{\frac{\sum(nv^2)}{N}}

  rms=\sqrt{\frac{2^2+2(3)^2+3(5)^2+4(8)^2+3(9)^2+2(15)^2}{15}}

  rms=\sqrt{69.73}

  rms=8.4m/s

c

Generally the most probable speed is 8m/s as it the most posses by particles being the average

4 0
3 years ago
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