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3 years ago

Tell whether the given equation has the ordered pair as a solution. y=-x -2;(2,-4)

Mathematics

2 answers:

motikmotik3 years ago

4 0

Yes the given equation has the offered pair as a solution

Sophie [7]3 years ago

4 0

Yes, the order pair is a solution

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I need help I dont understand

svp [43]

Answer:

X=5

mde=e

mef=5

mdfg=77

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP!!!! PLEASE! EASY!! BRAINLIEST RIGHT AWAY IF YOU EXPLAIN!!!

White raven [17]

Answer:

First picture: 60

Second picture:

Step-by-step explanation:

The first step for the first picture is to find the area of the triangle on top. In order to do that, we have to use the equation: (W*L*1/2)

(3*4*1/2)=6

Then, we multiply the above equation by the Height. Which makes the equation become 60.

The first step for the second picture is the same. We first find the area of the triangle on top.

(12*9*1/2)=54

Then we multiply the height by our above answer.

(54*20)=1,080

The other measurements that were there aren't needed. So, next time, completely ignore them!

Hope you have a good day/night! Good luck!

3 0

3 years ago

Read 2 more answers

In triangle UVW , the measure of angle W=90^ , the measure of angle U=31^ °, and UV = 31 feet. Find the length of VW to the near

Basile [38]

Answer:

Step-by-step explanation:

VW, also know as side X (as shown in image) can be found using the sine. Sin(theta)=opposite/hypotenuse. In this case, theta is 31 degrees and the hypotenuse is 31 feet. Plugging in all known values, we would have sin(31)=x/31. Rearrange the equation and isolate X on one side. Then use a calculator to find the answer. Good luck!

8 0

3 years ago

30 POINTS,NEED HELP ASAP !!!

zaharov [31]

Answer: OPTION A.

Step-by-step explanation:

You can observe that in the figure CDEF the vertices are:

$C(-2,-1),\ D(-2,0),\ E(2,2)\ and\ F(2,1)$

And in the figure C'D'E'F' the vertices are:

$C'(-8,-4),\ D'(-8,0),\ E'(8,8)\ and\ F'(8,4)$

For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:

For C'(-8,-4) and C(-2,-1):

$\frac{-8}{-2}=4\\\\\frac{-4}{-1}=4$

Let's choose another vertex. For E'(8,8) and E(2,2):

$\frac{8}{2}=4\\\\\frac{8}{2}=4$

You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.

Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:

$(x, y)$ → $(4x, 4y)$