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3 years ago

Solve the system using the elimination method.

2 answers:

Taya2010 [7]3 years ago

7 0

By adding the 1st and third equation together, you get rid of z and end with 7x+8y=13. The second equation will be the second equation and 2 times the first equation, so the will yield 3x+8y=1. Now, you solve this system of equations and get x3, y=-1, and z=-4

eimsori [14]3 years ago

4 0

Answer:

That's wrong...

Solve using determinants:

x + 4y − z = −14

5x + 6y + 3z = 4

−2x + 7y + 2z = −17

|A| = -120

|Ax| = -240

|Ay| = 360

|Az| = -480

x = 2

y = -3

z = 4

Step-by-step explanation:

Solving a 3 x 3 Linear System Using Cramer's Rule

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Tyler went to the supermarket to buy food for a food pantry. He has $36, and can carry up to 20 pounds of food in his backpack.

sattari [20]

Answer:

Solutions: (2,10), (4,5)

Not solutions: (1,12), (6,10), (12,8), (18,6)

Step-by-step explanation:

Let x be the number of packages of pasta and y be the number of jars of pasta sauce. If pasta costs $1 for a 1-pound package, then x packages of pasta cost $x and weigh x pounds. If pasta sauce costs $3 for a 1.5 pound jar, then y jars cost $3y and weigh 1.5y pounds.

1. Tyler has $36, then

$x+3y\le 36.$

2. Tyler can carry up to 20 pounds of food in his backpack, then

$x+1.5y\le 20.$

You get the following system of inequalities:

$\left\{\begin{array}{l}x+3y\le 36\\ x+1.5y\le 20\end{array}\right.$

Now substitute the coordinates of each point:

(1,12):

$\left\{\begin{array}{l}1+3\cdot 12=37> 36\\ 1+1.5\cdot 12=19\le 20\end{array}\right.$

False, because first inequality doesn't hold.

(2,10):

$\left\{\begin{array}{l}2+3\cdot 10=32\le 36\\ 2+1.5\cdot 10=17\le 20\end{array}\right.$

True, both inequalities hold.

(4,5):

$\left\{\begin{array}{l}4+3\cdot 5=19\le 36\\ 4+1.5\cdot 5=11.5\le 20\end{array}\right.$

True, both inequalities hold.

(6,10):

$\left\{\begin{array}{l}6+3\cdot 10=36\le 36\\ 6+1.5\cdot 10=21> 20\end{array}\right.$

False, because secondt inequality doesn't hold.

(12,8):

$\left\{\begin{array}{l}12+3\cdot 8=36\le 36\\ 12+1.5\cdot 8=24> 20\end{array}\right.$

False, because second inequality doesn't hold.

(18,6):

$\left\{\begin{array}{l}18+3\cdot 6=36\le 36\\ 18+1.5\cdot 6=27> 20\end{array}\right.$

False, because second inequality doesn't hold.

7 0

3 years ago

Helppppp me please .

kari74 [83]

Answer:

stuff

Step-by-step explanation:

180-72 = 108

a2 = 108º

a3 = 108

a4 = 72

a4+a6 = 180 so

a11+a13 + 180...

5 0

3 years ago

Write an equation in slope-intercept form of the line that passes through (-1,4) and (0,2).

ratelena [41]

Answer:

1,3

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Can someone help me with this question? Thank you!

Harrizon [31]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's evaluate ~

The given expression is :

$\qquad \sf \dashrightarrow \:4x + 8$

plug the value of x as 3

$\qquad \sf \dashrightarrow \:4(3) + 8$

$\qquad \sf \dashrightarrow \:12 + 8$

$\qquad \sf \dashrightarrow \:20$

Therefore, the required value is 20

8 0

2 years ago

Which graph shows the solution to the system of linear inequalities?

Brilliant_brown [7]

Answer:

this is answer

Step-by-step explanation:

To graph a linear inequality in two variables (say, x and y ), first get y alone on one side. Then consider the related equation obtained by changing the inequality sign to an equality sign. The graph of this equation is a line. If the inequality is strict ( < or > ), graph a dashed line.

4 0

2 years ago