Answer:
5.744
Step-by-step explanation:
the answer is 5.744 hope it helps!
Answer:
what do you mean
Step-by-step explanation:
9514 1404 393
Answer:
A, C
Step-by-step explanation:
The attached graph shows which lines go through the given point. They are ...
y = 1/2x -1 . . . . 1st selection
y = -1/6x +3 . . . 3rd selection
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The equations can be found algebraically by substituting the given point in the equation and seeing if the result is a true statement.
a) 2 = (1/2)(6) -1 = 3 -1 . . . true
b) 2 = -3(6) . . . . false
c) 2 = -1/6(6) +3 = -1 +3 . . . true
d) 2 = 2/3(6) -1 = 4 -1 . . . . false
e) 2 = 4(6) -2 = 24 -2 . . . . false
f) 2 = -3/2(6) +6 = -9 +6 . . . . false
Perpendicular line always have slopes that are negative reciprocals of one another. Mathematically,
m1*m2=-1
So to be perpendicular to the line given, let's rearrange it to the point slope form of a line...
3y=6x ?3 (not sure what you wanted to type there)
anyway isolating y by dividing both side by three will leave 2x where 2 is the slope.
So for the other line to be perpendicular, m*2=-1, m=-1/2, now we have:
y=-x/2 +b, we can now you the point given to solve for b
4=-2/2 +b
4=-1+b
b=5 so
y=-x/2 +5 or more neatly
y=(10-x)/2