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2 years ago

Hi hi um help. i'm too tired to think.

Mathematics

2 answers:

leva [86]2 years ago

5 0

Answer:

I think 66?

I hope it is if it’s not I’m sorry

Step-by-step explanation:

ValentinkaMS [17]2 years ago

4 0

Felt lol. but if i’m not mistaken it would be 66. feel free to bully me if i’m wrong

You might be interested in

The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am

posledela

Step-by-step walkthrough:

Well a standard half-life equation looks like this.

$N = N_0 * (\frac{1}{2})^{t/p$

$N_0$ is the starting amount of parent element.

$N$ is the end amount of parent element

$t$ is the time elapsed

$p$ is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days$

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2} = 37g$

Now we just gotta do some algebra. Use the original function but this time, replace $N(t)$ with 10g and solve algebraically.

$10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}$

Take the log of both sides.

$log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})$

Use the exponent rule for log laws that, $log(b^x) = x*log(b)$

$log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})$

$\frac{log(\frac{5}{37})}{log(\frac{1}{2})} = \frac{t}{2.8days}$

$2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})} = t$

slap that in your calculator and you get

$t = 8.1 days$

7 0

2 years ago

Simplify the expression 6[8+8](3+7)] ?

krok68 [10]

Answer:

960

Step-by-step explanation:

6[8+8](3+7)

Parentheses first

6[16] (10)

Then multiply from left to right

96*10

960

7 0

3 years ago

Read 2 more answers

HIGH SCHOOL GEOMETRY/ ALGEBRA

max2010maxim [7]

Answer:

The ratio of the lateral sides and perimeters = the ratio of square root of their areas

Then, the ratio of the sides and the perimeters is 6:5 or if this is wrong it it is 5:6

if this helps plz mark as brainliest

3 0

3 years ago

A rectangle basin is being filled with water. The basin is 7 feet long, 12 feet wide, and 4 feet high. How much water is going t

stira [4]

In this problem your going to need to find volume.

The formula for volume of a rectangular prism (Which is what we are trying to find)

Is Volume = Length x Height x Width

So in your problem we can create the equation:
7 x 4 x 12 = Your answer.

7 x 4 = 28
28 x 12 = 336.

Your going to need 336 feet^3 (D)

Hope this helps!
Brainliest is always appreciated if you feel its deserved.

4 0

3 years ago

The area of a regular octagon is 35 cm^2. What is the area of a regular octagon with sides five times as long?

Marat540 [252]

So... let's say the smaller regular octagon has sides of "x" long, then the larger octagon will have sides of 5x.

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\$

$\bf \cfrac{small}{large}\quad \stackrel{area~ratio}{\cfrac{s^2}{s^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{(5x)^2}}\implies \stackrel{area~ratio}{\cfrac{x^2}{5^2x^2}}\implies \stackrel{area~ratio}{\cfrac{\underline{x^2}}{25\underline{x^2}}}=\stackrel{area~ratio}{\cfrac{35}{a}}
\\\\\\
\cfrac{1}{25}=\cfrac{35}{a}\implies a=\cfrac{25\cdot 35}{1}$

3 0

3 years ago