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3 years ago

Why is 186,426 divisible by 3 and 9

1 answer:

7 0

The divisibility rule
For example
The divisibility rule for three is adding the number together
1+8+6+4+2+6= 27
And 3 is divisible by 27
And for nine
It’s similar to three

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Consider the arithmetic sequence 10, 8, 6, 4, ....

Gekata [30.6K]

Answer:

12 - 2n

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 10 and d = 8 - 10 = - 2, thus

$a_{n}$ = 10 - 2(n - 1) = 10 - 2n + 2 = 12 - 2n

4 0

3 years ago

Read 2 more answers

Consider F and C below. F(x, y) = x4y5i + x5y4j, C: r(t) = t3 − 2t, t3 + 2t , 0 ≤ t ≤ 1 (a) Find a function f such that F = ∇f.

vovikov84 [41]

$\mathbf f(x,y)=x^4y^5\,\mathbf i+x^5y^4\,\mathbf j$

We want a scalar function $f(x,y)$ whose gradient is equivalent to the vector field. That means

$\dfrac{\partial f}{\partial x}=x^4y^5\implies f(x,y)=\dfrac{x^5y^5}5+g(y)$
$\dfrac{\partial f}{\partial y}=x^5y^4\implies x^5y^4=x^5y^4+\dfrac{\mathrm dg}{\mathrm dy}$
$\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C$

So (a)

$f(x,y)=\dfrac{x^5y^5}5+C$

which means (b)

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(\mathbf r(1))-f(\mathbf r(0))=f(-1,3)-f(0,0)=-\dfrac{243}5-0=-\dfrac{243}5$

5 0

3 years ago

33 photos into 2 groups so the ratio is 4/7

andrew-mc [135]

So 33/2 is 11.5 and 11.5=23/2

7 0

3 years ago

What is the solution of the equation 4x + 3y = 12 7x + 5y = 26

malfutka [58]

The solution would be B) (18,-20)

4 0

3 years ago

A. [-1, 1]<br> b. [0, pi] <br> c. [-pi/2, pi/2]<br> d. -♾, ♾]

meriva

f(x) = sin(x)

Domain (–∞, ∞)

Range [–1, 1]

y = arcsine(x)

y = f–¹(x)

Domain [–1, 1]

Range [–π/2, π/2]

6 0

3 years ago