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Elena L [17]
3 years ago
9

What is the temperature of 1.485 moles of N₂ gas at a pressure of 1.072 atm and a volume of 20 L?

Chemistry
1 answer:
morpeh [17]3 years ago
8 0

Answer:

178.67K

Explanation:

PV=nRT

T=PV/nR

= 1.072atm*20L/1.485mol*0.0821LatmK^-1

=178.67K

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Calcium chlorate has the formula Ca(ClO3)2. Which best describes the structure of calcium chlorate? One molecule of calcium chlo
deff fn [24]
The formula Ca(ClO3)2 breaks down to: 1 calcium atom, 2 chlorine atoms, and 6 oxygen atoms. Therefore:

One molecule of calcium chlorate contains 9 atoms [correct]

Calcium chlorate is not an element, nor does the molecule contain only 3 atoms [incorrect]

It does not take 9 different elements - just the three elements we listed [incorrect]

Calcium chloride only contains one Ca group [incorrect]


6 0
3 years ago
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The addition of perchloric acid to pure water causes the conductivity to _________.
Olin [163]
Adding perchloric acid to water would cause it's conductivity to increase.
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3 years ago
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 Consider a bathtub filled with water, with a plug in the drain. How long would this be considered a closed system?
Monica [59]
For a closed system, you need two things:
1) a conservation of mass within the boundaries of the system
2) the ability to freely exchange energy to & from the "closed" system with a surrounding external system


So, the answer is <u><em>never</em></u>, since your defining the "system" as the water within the bathtub, and an open bathtub is exposed to evaporation, which is not conserving mass within the defined "system".
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3 years ago
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What are observations that indicate a chemical change has occurred ?
sukhopar [10]

Answer:

Change of odor

Change of color

Change in temperature

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4 0
3 years ago
A certain organ pipe, open at both ends, produces a fundamental frequency of 272 HzHz in air. Part A If the pipe is filled with
vladimir2022 [97]

Answer:

fundamental frequency in helium = 729.8 Hz

Explanation:

Fundamental frequency of an ope tube/pipe = v/2L

where v is velocity of sound in air = 340 m/s; λ is wave length of wave = 2L ; L  is length of  the pipe

To find the length of the pipe,

frequency  = velocity of sound / 2L

272 = 340 / 2 L

L = 0.625 m

If the pipe is filled with helium at the same temperature, the velocity of sound will change as well as the frequency of note produced since velocity is directly proportional to frequency of sound.

Also, the velocity of sound is inversely proportional to  square root of molar mass of gas; v ∝ 1/√m

v₁/v₂ = √m₂/m₁

v₁ = velocity of sound in air, v₂ = velocity of sound in helium, m₁ = molar mass of air, m₂ = molar mass of helium

340 / v = √4 / 28.8

v₂ = 340 / 0. 3727

v₂  =  912.26  m /s  

fundamental frequency in helium  = v₂ / 2L

fundamental frequency in helium = 912.26 / (2 x 0.625)

fundamental frequency in helium = 729.8 Hz

7 0
2 years ago
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