I believe that it would be false. <span>The name of the ion P3- is not phosphoride ion but it is phosphide ion. </span><span>The </span>phosphide ion<span> is P </span>3−<span>, and </span>phosphides<span> of almost every metal in the periodic table are known. They exhibit a wide variety of chemical and physical properties. Hope this answers the question.</span>
Answer is: boiling point will be changed by 4°C.
Chemical dissociation of aluminium nitrate in water: Al(NO₃)₃ → Al³⁺(aq) + 3NO⁻(aq).
Change in boiling point: ΔT =i · Kb · b.
Kb - molal boiling point elevation constant of water is 0.512°C/m, this the same for both solution.
b - molality, moles of solute per kilogram of solvent., this is also same for both solution, because ther is same amount of substance.
i - Van't Hoff factor.
Van't Hoff factor for sugar solution is 1, because sugar do not dissociate on ions.
Van't Hoff factor for aluminium nitrate solution is approximately 4, because it dissociates on four ions (one aluminium cation and three nitrate anions). So ΔT is four times bigger.
Answer:
i believe its called A. periods
The reaction will shift toward the reactants if the volume is cut in half.
<h3 /><h3>Reactants </h3>
The initial components of a chemical reaction are called reactants. Chemical bonds between reactants are broken and new ones are created in order to create products. Reactants and products are listed on the left and right sides, respectively, of the arrow in a chemical equation.
Substances on both sides of an arrow that points left and right are both reactants and products in a chemical process (the reaction proceeds in both directions simultaneously). A chemical equation that is balanced has the same amount of atoms of each element in the reactants and products. Around 1900–1920 is when the word "reactant" was first used. There are instances when the word "reagent" is interchangeable.
Learn more about reactants here:
brainly.com/question/17096236
#SPJ4
Answer:
See explanation
Explanation:
If we look at the electron configuration closely, we will discover that the element must have had a ground state electron configuration of 2,4.
This is because, the innermost shell usually holds two electrons while the outer shells hold eight electrons each. The four electrons must be accommodated in the second shell in the ground state configuration of the compound.
However, when the atom is excited, one electron from this shell may move to the third shell to give the excited state configuration 2-3-1 as shown in the question.
