<span>Mutation. Either exchanging a Purine with another Purine, Pyrimidin with another Pyrimidin, or completely exchanging a Purine with a Pyrimidin or vice versa. Point- or Frameshift-Mutation.</span>
Answer:
Hello your question is poorly written below is the well written question
Explore what molecules you can build From Lewisstructureandmoleculargeometry . What are the combinations attached groups, atoms, or lone pairs you can add to a central atom?
answer :
- when there are three ( 3 ) groups and a lone pair the shape of the molecule will be pyramidal but when the three ( 3 ) groups does not have any lone pair attached to it, the shape of the molecule will be trigonal planar
- When there are two groups and two lone pairs the shape of the molecule will be bent while when there are two groups without lone pairs the shape of the molecule will be linear
Explanation:
From molecular Geometry changes there are two groups to be considered here and they are group and lone pairs
<u>The combinations that can be added to a central atom </u>
when there are three ( 3 ) groups and a lone pair the shape of the molecule will be pyramidal but when the three ( 3 ) groups does not have any lone pair attached to it, the shape of the molecule will be trigonal planar
When there are two groups and two lone pairs the shape of the molecule will be bent while when there are two groups without lone pairs the shape of the molecule will be linear
Answer:
The relationship is expressed as follows: ![K_{a} = \frac{[H+][A-]}{[HA]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D)
Explanation:
Most acidic substances are weak acids and are therefore only partially ionized in acqeous solution. We cab use the equilibrium constant for the ionization of acid to express the extent to which the weak acid ionizes. If we represent a general weak acid as HA, we can write the equation for its ionization reaction like this:
To calculate the pH of a weak acid, we use the equilibrium concentration of the reacted species and product.
Take for example:
HA → H + A⁻
where A id the conjugate base.
Knowing that x amount of acid reacts, we can solve like this:
HA → H + A⁻
H+ = antilog (pH)
thus, the pH of the acid is equals to H+ (initial) - H+ (equilibrium) ≈ H+ (initial)
Answer:
you would need to multiply 50 times 2 wich is 100 so i beleive its 100
Explanation:
