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Alinara [238K]
3 years ago
6

Calcium chlorate has the formula Ca(ClO3)2. Which best describes the structure of calcium chlorate? One molecule of calcium chlo

rate contains nine atoms. Calcium chlorate is an element that contains three atoms. It takes nine different elements to make one molecule of calcium chlorate. Calcium chlorate contains two Ca groups.
Chemistry
2 answers:
USPshnik [31]3 years ago
8 0

Answer: One molecule of calcium chlorate contains 9 atoms

Explanation:

hey if you what to give me brainliest that would be great!

deff fn [24]3 years ago
6 0
The formula Ca(ClO3)2 breaks down to: 1 calcium atom, 2 chlorine atoms, and 6 oxygen atoms. Therefore:

One molecule of calcium chlorate contains 9 atoms [correct]

Calcium chlorate is not an element, nor does the molecule contain only 3 atoms [incorrect]

It does not take 9 different elements - just the three elements we listed [incorrect]

Calcium chloride only contains one Ca group [incorrect]


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When 8.0 grams of sodium hydroxide is dissolved in sufficient water to make 400. mL of solution, what is the concentration of th
nata0808 [166]

Answer:

The concentration of this sodiumhydroxide solutions is 0.50 M

Explanation:

Step 1: Data given

Mass of sodium hydroxide (NaOh) = 8.0 grams

Molar mass of sodium hydroxide = 40.0 g/mol

Volume water = 400 mL  = 0.400 L

Step 2: Calculate moles NaOH

Moles NaOH = mass NaOH / molar mass NaOH

Moles NaOH = 8.0 grams / 40.0 g/mol

Moles NaOh = 0.20 moles

Step 3: Calculate concentration of the solution

Concentration solution = moles NaOH / volume water

Concentration solution = 0.20 moles / 0.400 L

Concentration solution = 0.50 M

The concentration of this sodiumhydroxide solutions is 0.50 M

6 0
3 years ago
A sealed 1.0L flask is filled with 0.500 mols of I_2 and 0.500 mols of Br_2. When the container achieves equilibrium the equilib
DochEvi [55]

Answer:

[IBr] = 0.049 M.

Explanation:

Hello there!

In this case, according to the balanced chemical reaction:

I_2+Br_2\rightarrow 2IBr

It is possible to set up the following equilibrium expression:

K=\frac{[IBr]^2}{[I_2][Br_2]} =0.0110

Whereas the the initial concentrations of both iodine and bromine are 0.50 M; and in terms of x (reaction extent) would be:

0.0110=\frac{(2x)^2}{(0.50-x)^2}

Which can be solved for x to obtain two possible results:

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Whereas the correct result is 0.0245 M since negative results does not make any sense. Thus, the concentration of the product turns out:

[IBr]=2x=2*0.0249M=0.049M

Regards!

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Could someone please tell show me steps to solve this, I am so confused.
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And this is y I should of paid attention in that one science class in middle school that taught this...

( ̄▽ ̄;)

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3 years ago
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