Answer:
The dimension of the play area written algebraically is y²/2 + 9y
Step-by-step explanation:
Let the be x and the width be y
If the length is to be 9 feet longer than half the width,
hence y/2 + 9 = x
hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y
Answer:
x > 2
x ∈ ( +2 ; + oo )
Step-by-step explanation:
8 - 2x < 4
8 - 4 < 2x
4 < 2x | : 2
2 < x
x > 2
x ∈ ( +2 ; + oo )
Answer:
multiply the legth times width
Step-by-step explanation:
First number: x = 19
Second number: Y = -5
x + 2y = 9
2x + y = 33
