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Vinvika [58]
3 years ago
11

A doctor observes a graph that shows the electrical activity (in volts) of the heart of a patient over a period of time (in seco

nds). Each local maximum of 0.004 volts corresponds to one heartbeat. The doctor needs to calculate the heart rate of the patient in beats per minute. What is the heart rate of this patient?
____ beats per minute
​

Mathematics
2 answers:
Doss [256]3 years ago
7 0

Answer:

60 beats per minute

Step-by-step explanation:

I just did it on Khan and it was correct.

hodyreva [135]3 years ago
6 0

Answer:

90 beats per minute

Step-by-step explanation:

By looking at the graph, we see that exactly at second 6, the 9th beat occurs. We can take that to beats/min by multiplying that relation by 10 (since there are ten 6sec in one minute).

9beats every 6sec * 10 = 90beats/min

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(8c+8)–(c+3)<br> answer-
otez555 [7]

Answer:

7c + 5

Step-by-step explanation:

(8c+8)–(c+3)

8c - c = 7c

8 - + 3 = 5

7c + 5

6 0
3 years ago
Read 2 more answers
Evaluate each trigonometric equation for θ.
liberstina [14]

Answer:

sinФ = 8/17

cosФ = 15/17

tan Ф = 8/15

csc Ф = 17/8

sec Ф = 17/15

cot Ф = 15/8

Step-by-step explanation:

Let us revise the trigonometry functions

  • Sin(x) = opposite/hypotenuse
  • Cos(x) = adjacent/hypoteouse
  • Tan(x) = opposite/adjacent
  • Csc(x) = hypotenuse/opposit
  • Sec(x) = hypotenues/adjacent
  • Cot(x) = adjacent/opposite

In the given figure

The opposite side to angle Ф = 8

The adjacent side to angle Ф = 15

Find the hypotenuse using Pythagoras' theorem

Hypotenuse = \sqrt{8^{2}+15^{2}  }

Hypotenuse = \sqrt{64+225}

Hypotenuse = \sqrt{289}

Hypotenuse = 17

Let us use the rules above to find the trigonometry functions

sinФ = 8/17

cosФ = 15/17

tan Ф = 8/15

csc Ф = 17/8

sec Ф = 17/15

cot Ф = 15/8

4 0
3 years ago
What are the values of x for which the denominator is equal to zero for y= -x+4/xx+6X+8
Veseljchak [2.6K]

Answer:

-4 and -2

Step-by-step explanation:

(X+4)(x+2)

4×2=8

4+2=6

8 0
3 years ago
What is the equation of the line that is parallel to the given line and passes through the point (−3, 2)?
enyata [817]
You forgot to include the given line.

We need the given line to find the slope. The slope of parallel lines are equal. So, the slope of the line of the equation you are looking for is the same slope of the given line.

I can explain you the procedure to help you to find the desired equation:

1) Slope

Remember that the slope-intercept equation form is y = mx + b where m is the slope and b is thye y-intercept.

If you clear y in every equation you get:

a) y = (3/4)x + 17/4 => slope = 3/4

b) y = (3/4)x + 20/4 = (3/4)x + 5 => slope = 3/4

c) y = -(4/3)x - 2/3 => slope = -4/3

d) y = (-4/3)x - 6/3 = (-4/3)x - 2 => slope = -4/3

So, you just have to compare the slope of the given line with the above slopes to see which equations are candidates.

2) Point (-3,2)

You  must verify which equations pass through the point (-3,2).

a) 3x - 4y = - 17

3(-3) - 4(2) =  -17
- 9 - 8 = - 17
- 17 = - 17 => it is candidate

b) 3x - 4y = - 20

- 17 ≠ - 20 => it is not candidate

c) 4x + 3y = - 2

4(-3) + 3(2) = - 2
-12 + 6 = - 2
-6 ≠ -2 => it is not candidate

d) 4x + 3y = - 6

   -6 = - 6 => it is candidate

3) So, the point (-3,2) permits to select two candidates

3x - 4y = - 17, and 4x + 3y = -6.

4) Yet you have to find the slope of the given equation, if it is 3/4 the solutions is the equation 3x - 4y = -17; if it is -4/3 the solution is the equation 4x + 3y = -6.
6 0
3 years ago
Read 2 more answers
The segments shown below could form a triangle.
erastovalidia [21]

sorry i don,t unerstan what u wn,t

8 0
3 years ago
Read 2 more answers
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